Answer:
The solution to your inquiry is C = 0.000333 kcal/g°C
or C = 0.333 cal/g°C
Explanation:
Data
Q = 1.67 kcal
mass = 79.2 g
ΔT = 63.3°C
Formula
Q = mCΔT
Solving for C
C = Q/mΔT
Substituting values
C = 1.67/(79.2 x 63.3)
Simplifying
C = 1.67 / 5013.4
Final Result
C = 0.000333 kcal/g°C
or C = 0.333 cal/g°C
Answer:
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
Explanation:
- To balance chemical equations, coefficients are assigned to both reactants and products.
- This yields an equal count of atoms of each element on both sides of the equation.
- Balancing chemical equations ensures compliance with the law of conservation of mass.
- According to this law, the mass of reactants must equal the mass of products, achievable through balancing the equation.
- The application of coefficients 2, 3, 4, 4, 4 allows for an equal balance in the equation.
- Consequently, the balanced equation can be written as:
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
I believe you mean KO2 reacting with H2O. The reaction is 4KO2+2H2O->4KOH +3O2. The mole ratio O2:KO2 is 3:4. Thus moles of O2 produced = 0.500/4*3 = 0.375 mol.
