1 hour = 3,600 seconds
1 km = 1,000 meters
75 km/hour = (75,000/3,600) m/s = 20-5/6 m/s
The mean speed during the deceleration is
(1/2)(20-5/6 + 0) = 10-5/12 m/s.
Traveling at this average speed for 21 seconds,
the bus covers
(10-5/12) × (21) = 218.75 meters.
Answer:
The distinction between the locations of the two events as perceived in S is calculated to be 4.42 x 10^8 m
Explanation:
The time dilation concept has been utilized to address this question, as detailed in the attachment.
To tackle this question, we know the following:
1 Albert equals 88 meters.
1 A = 88 m.
Initially, we square both sides of the equation:
(1 A)^2 = (88 m)^2
1 A^2 = 7,744 m^2
<span>Since 1 acre equals 4,050 m^2, let’s divide both sides by 7,744 to find out how many acres match this value:</span>
1 A^2 / 7,744 = 7,744 m^2 / 7,744
(1 / 7,744) A^2 = 1 m^2
Then multiply both sides by 4,050.
(4050 / 7744) A^2 = 4050 m^2
0.523 A^2 = 4050 m^2
<span>Thus, one acre is approximately 0.52 square alberts.</span>
