The amount of work performed by a system at consistent pressure is defined by the following equation:

where
p represents pressure

as the final volume

as the initial volume
Plugging the values given in this case into the formula gives us

Considering that

, the result for the work done becomes
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mass₃<mass₁=mass₅<mass₂=mass₄
Explanation:
Data points:-
1. mass: m speed: v
2. mass: 4 m speed: v
3. mass: 2 m speed: ¼ v
4. mass: 4 m speed: v
5. mass: 4 m speed: ½ v
We know that the formula for Kinetic energy (KE) is ½ mv²
Where m represents the mass of the object
v represents the object's velocity
<psubstituting the="" given="" values="" for="" mass="" and="" speed="" from="" previous="" data:="">
The KE of Body 1(mass₁) = ½*m*v² = mv²/2
KE of Body 2(mass₂) = ½*4m*v² = 2mv²
KE of Body 3(mass₃) = ½*2m*(1/4v)² = mv²/16
KE of Body 4(mass₄) = ½*4m*v ² = 2mv
²
KE of Body 5(mass₅) = ½*4m*(1/2v)² = mv²/2
</psubstituting>