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polet
13 days ago
13

Which statements describe the relationship between the area and the biodiversity of an ecosystem? Check all that apply. Large ec

osystems always have higher biodiversity than smaller ecosystems. A large area of a forest will likely have higher biodiversity than a smaller area of the same forest. A half acre of rainforest would likely have greater biodiversity than a full acre of desert. Small ecosystems always have low biodiversity. The same area of two different types of ecosystems will have the same biodiversity.
Physics
2 answers:
Ostrovityanka [942]13 days ago
9 0
The right options are B. A larger section of forest is likely to possess higher biodiversity than a smaller segment of the same forest. C. A half acre of rainforest would very likely contain more biodiversity than a full acre of desert.
Yuliya22 [1.1K]13 days ago
3 0
A larger section of a forest is likely to support more diverse species compared to a smaller section of the same forest. Additionally, a half acre of rainforest is expected to exhibit more biodiversity than a full acre of desert. Biodiversity refers to the variety found within an ecosystem, which encompasses differences among living organisms based on their species and habitats. Generally, ecosystems with larger areas tend to have greater biodiversity; hence, a substantial forest area would likely harbor more biodiversity than a smaller area within it. Similarly, the previous example illustrates that a half acre of rainforest would likely have a higher level of biodiversity compared to one acre of a desert.
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Ben walks 500 meters from his house to the corner store. He then walks back toward his house, but continues 200 meters past his
Keith_Richards [1021]
Velocity = 71 meters per minute (MPM)
S stands for Speed
D means Distance
T represents Time
To calculate Speed, divide Distance by Time.
6 0
14 days ago
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If the coefficient of static friction between a table and a uniform massive rope is μs, what fraction of the rope can hang over
inna [987]
Here's the procedure explained: Assume F represents the portion of the rope that is extending over the table. In this scenario, the frictional force that holds the rope on the table can be calculated using the formula: Ff = u*(1-f)*m*g. Additionally, it is important to determine the gravitational force that attempts to pull the rope off the table, Fg, calculated through: Fg = f*m*g. You then need to set these two equations equal to each other and resolve for f: f*m*g = u*(1-f)*m*g leads to f = u*(1-f) = u - uf. Simplifying gives f + uf = u, which results in f = u/(1+u) representing the fraction of the rope. This will lead you to the final answer.
8 0
1 day ago
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What is the sources of error and suggestion on how to overcome it in the hooke's law experiment?
Yuliya22 [1153]
In the study of physics, Hooke's law can be expressed as:

F = kx

This law indicates that the spring force F is proportional to the extension x, with k being the spring constant.

In experiments, this is often examined using the setup illustrated in the included figure. The spring is tested, and a known weight is applied underneath it. This weight exerts a gravitational pull, essentially its weight, on the spring. While the spring elongates, the displacement can be measured using a ruler.

Several potential errors can arise during this experiment. Firstly, the person's measurement reading may be faulty. Digital scales offer greater accuracy as they reduce human error, while ruler readings can be subjective, especially if not viewed at eye level. Additionally, the object's weight may be inaccurately measured if the scale is untrustworthy. Lastly, the measuring equipment may not be correctly calibrated.

6 0
20 hours ago
If you are anchored in a fixed spot, and a set of six waves pass underneath you during a 60 second time interval, what is the wa
Ostrovityanka [942]

Answer:

Explanation:

Within a duration of 60 seconds, six waves are observed.

With a total of 6 waves,

this equates to 3 wavelengths.

As a result,

the period for each wavelength is calculated as 60 divided by 3.

Thus, period = 20 seconds.

According to the frequency-period relationship,

f = 1 / T

f = 1 / 20

f = 0.05 Hz

5 0
2 days ago
A box sliding on a horizontal frictionless surface runs into a fixed spring, compressing it a distance x1 from its relaxed posit
serg [1189]

Answer:

x₂=2×1

Explanation:

According to the work-energy theorem, we can assume that the gravitational potential energy at the lowest point of compression is zero since the kinetic energy change is 0;

mgx-(kx)²/2 =0 where m refers to the object's mass, g indicates the acceleration due to gravity, k denotes spring constant, and x represents the spring's compression.

mgx=(kx)²/2

x=2mg/k----------------compression when the object is at rest

However, ΔK.E =-1/2mv²⇒kx²=mv² -----------where v symbolizes the object's velocity and K.E signifies kinetic energy

Thus, if kx²=mv² then

v=x *√(k/m) ----------------where v=0

<pDoubling v results in multiplying x *√(k/m) by 2, leading to x₂ being double x₁

7 0
11 days ago
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