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olga55
23 days ago
13

Arrange the movement/act/organization in ascending order of occurrence. Energy Supply and Environmental Coordination Act Nature

Conservancy Intergovernmental Panel on Climate Change (IPCC) Clean Water Act Federal Water Pollution Control Act Eastern Wilderness Act Water Quality Act Toxic Substances Control Act Clean Air Act Endangered Species Preservation Act ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓
Physics
1 answer:
Sav [3.1K]23 days ago
5 0

Response:

PLATO!!!!! THESE ARE ACCURATE!!! OTHER OPTIONS ARE INCORRECT. I JUST GOT IT RIGHT ON PLATO

Clarification:

1. federal water pollution control act

2.nature conservancy

3. clean air act

4. water quality act

5. endangered species preservation act

6. clean water act

7. energy supply and environmental coordination act

8. eastern wilderness act

9. toxic substance act

10. intergovernmental panel on climate change (IPCC).

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1. A 930-kg car traveling 56 km/h comes to a complete stop in 2.0 s. What is the
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The force exerted on the car during the stop measures 6975 N. Explanation: Given that the mass (m) is 930 kg, speed (s) at 56 km/h converts to 15 m/s, and the stopping time (t) is 2 s, we compute the force using F = m * a. Here, acceleration (a) can be obtained through a = s/t. The total force calculation confirms that F = 930 kg * (15 m/s) / 2 s results in 6975 N.
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20 days ago
This image shows the direction of the flow of water through a constricted pipe. Which of the following happens as you move from
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C. The rate of water flow diminishes.
6 0
21 day ago
If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
Maru [3345]

Answer:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

Consequently, the temperature difference across the material will be \Delta T = 375 K

Explanation:

In this case, we apply the Fourier Law of heat conduction expressed by the following equation:

Q = -kA \frac{\Delta T}{\Delta x}   (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 denotes the cross-sectional area

Q= 3KW signifies the heat transfer rate

\Delta T is the temperature difference we need to determine

represents the thickness of the material\Delta x=2.5 cm =0.025 m

To isolate \Delta T from equation (1), we obtain:

\Delta T =\frac{Q \Delta x}{Ak}

Initially, we convert 3KW to W, resulting in:

Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W

With all variables accounted for, we can substitute and calculate:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

Thus, the temperature difference across the material will be \Delta T = 375 K

5 0
20 days ago
On a guitar, the lowest toned string is usually strung to the E note, which produces sound at 82.4 82.4 Hz. The diameter of E gu
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The entire and thorough solution is included.

8 0
1 month ago
Lasers are classified according to the eye-damage danger they pose. Class 2 lasers, including many laser pointers, produce visib
kicyunya [3294]

Response:

a) 318.2 W/m^2

b) 2.5 x 10^-4 J

c) 1.55 x 10^-8 v/m

Reasoning:

The laser power P = 1 mW = 1 x 10^-3 W

duration t = 250 ms = 250 x 10^-3 s

Taking a beam diameter of 2 mm = 2 x 10^-3 m

therefore

the beam's cross-sectional area A = \pi d^{2} /4 = (3.142 x (2*10^{-3} )^{2})/4

A = 3.142 x 10^-6 m^2

a) The intensity I = P/A

where P refers to the laser's power

and A represents the beam's cross-sectional area

I = ( 1 x 10^-3)/(3.142 x 10^-6) = 318.2 W/m^2

b) The total energy delivered E =Pt

where P is the beam's power

and t is the exposure duration

E = 1 x 10^-3 x 250 x 10^-3 = 2.5 x 10^-4 J

c) The peak electric field can be computed as

E = \sqrt{2I/ce_{0} }

where I signifies the beam's intensity

and E is the electric field

c is the speed of light = 3 x 10^8 m/s

e_{0} = 8.85 x 10^9 m kg s^-2 A^-2

E = \sqrt{2*318.2/3*10^8*8.85*10^9} = 1.55 x 10^-8 v/m

6 0
19 days ago
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