Answer:
The change in the volume of a metallic dental filling caused by the temperature difference is 0.1143 mm.
Explanation:
Given:
Body temperature is, 
Temperature of the ice cream is, 
The filling's initial volume is, 
The thermal expansion coefficient is, 
It is known that the coefficient of volume expansion is associated with thermal expansion as follows:
Now, the change in volume for a metallic dental filling can be calculated as:
Thus, the change in volume for a metallic dental filling from the temperature variance is 0.1143 mm.
Answer:
(1) En to n-1 = 0.55 eV
(2) En-1 to n-2 = 0.389 eV
(3) ninit =4
(4) L =483.676 ×10^-11 nm
(5) λlongest= 1773.33 nm
Explanation:
The comprehensive details regarding the answer are provided in the attached files.
<span>θ=0.3sin(4t)
w=0.3cos(4t)(4)=1.2cos(4t)
a=-4.8sin(4t)
Knowing that the maximum of cos4t is always 1 (as seen in the cosine graph), similarly, sin4t will always equal 0
Thus, the maximum rate of w = 1.2 rad/s
vAmax=r*w=250*1.2=300 mm/s
(may vary if your graph/radius is derived from a different source)
adt=a*r=200*-4.8sin(4t)=0 (when sin(4t)=0)
adn=r*w^2=200*1.2^2=288
ad= the square root of adt^2 + adn^2 = 288 mm/s^2</span>
<span>Answer:
The correct response is
simply sum the two kinetic energies:
E = (1/2)mv^2 + (1/2)mv^2</span>
