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Nadusha1986
1 month ago
11

Which example illustrates a chemical change?

Physics
2 answers:
Yuliya22 [3.3K]1 month ago
8 0
<span>Chemical changes produce different substances or compounds. This occurs when atoms form new bonds, meaning the substance's composition is altered. Examples include rusting, combustion, and cooking food. Freezing and vaporization are physical changes, not chemical ones.</span>
Sav [3.1K]1 month ago
5 0

Answer:

Burning wood

Explanation: Although the material underwent burning, it no longer retains the same identity as before.

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The spring is now compressed so that the unconstrained end moves from x=0 to x=L. Using the work integral W=∫xfxiF⃗ (x⃗ )⋅dx⃗ ,
Sav [3153]

solution:

the spring force applied by a spring with spring constant k can be expressed as

F(x)=-kx

where k acts as the spring constant

and x indicates the spring's deformation

to determine the work completed by the spring

W=\int\limits^L_0 {} \, dW

the amount of work done by the spring when moving from x=0 to x=L

W=-kx^2/2

substituting the limits x=0 and x=L

we derive the work done in terms of k and L

ANSWER

W=-kL^2/2

4 0
1 month ago
A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by
kicyunya [3294]

Answer:

W = -510.98 J

Explanation:

Force = 43 N, 61° SW

Displacement = 12 m, 22° NE

The work done is calculated using:

W = F*d*cos(A)

where A is the angle between the applied force and displacement.

The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°

Hence, W = 43 * 12 * cos(172)

This results in W = -510.98 J

The negative result indicates that the work is done contrary to the direction of the force applied.

6 0
2 months ago
A floating balloon can be formed when the substance helium is released from a compressed container into a flat rubber balloon. T
Softa [3030]
When helium is released from a compressed container, the decompressed atoms expand and rise, causing the rubber balloon to inflate and float along. In this scenario, helium exists in a gaseous state.
6 0
1 month ago
Read 2 more answers
Wire A has the same length and twice the radius of wire B. Both wires are made of the same material and carry the same current.
serg [3582]

Answer:

V_A= \frac{I_A}{n_A e A_A}= \frac{I}{ne 4A_B}= \frac{1}{4} \frac{I}{neA_B}

V_B= \frac{I_B}{n_B e A_B}= \frac{I}{ne A_B}

Consequently, we find that:

V_A = \frac{1}{4} V_B

Thus, the most suitable answer would be:

a. vA = vB/4

Explanation:

In this situation, we can establish the following conditions:

L_A = L_B =L both wires share the same length

both wires carry an identical currentI_A = I_B =I

Both wires are constructed of the same material, indicating that the electron density (n) remains constant across both wires

n_A = n_B =n

We also know that r_A = 2 r_B where r signifies the radius.

Given that wires are cylindrical in shape, we can determine the area for each case:

A_A= \pi r^2_A = \pi (2r_B)^2 = 4 \pi r^2_B= 4 A_B

A_B = \pi r^2_B

Thus, we conclude that

A_A = 4 A_B

Now we are aware that the drift velocity of an electron in a wire can be described by:

v_d = \frac{I}{neA}

Where I denotes the current, n is the electron density, e represents the electron charge, and A signifies the area.

By substituting, we arrive at:

V_A= \frac{I_A}{n_A e A_A}= \frac{I}{ne 4A_B}= \frac{1}{4} \frac{I}{neA_B}

V_B= \frac{I_B}{n_B e A_B}= \frac{I}{ne A_B}

So we observe that:

V_A = \frac{1}{4} V_B

Thus, the most fitting answer is:

a. vA = vB/4

6 0
1 month ago
An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force
serg [3582]
The gravitational force acting on the elevator is 4500N. Explanation: The parameters provided indicate that the force exerted by the elevator is F = 4500 N. The elevator does not accelerate. According to Newton's third law, the force exerted by the cable matches the gravitational force on the elevator, which represents its weight (W), and the elevator's motion stands as follows: F = W + (Mass of elevator × Acceleration of elevator). Therefore, F = W + (Mass of elevator × 0) = W, which leads us to F = 4500 N = W. The net force on the elevator can be expressed as F - W = 0, confirming that the gravitational force on the elevator equals W = 4500N.
3 0
1 month ago
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