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Aleksandr
7 days ago
15

An electric kettle uses electrical energy to boil water. Energy from the electricity is transferred to the water, heating it up.

An electric ice maker also uses electrical energy, but it freezes water to form ice. Since energy can’t be created or destroyed, and water loses potential energy when it freezes to form ice, what happens to the energy put into the ice maker and the energy released by the water?
Chemistry
1 answer:
eduard [2.6K]7 days ago
4 0
In the electrical ice maker, water releases energy as it freezes into ice, translating this energy into bond energy. Although there are hydrogen bonds in the liquid water state, adding electrical energy converts the water from liquid to solid, increasing bond strength. The potential energy from the water is now represented as hydrogen bond energy in the ice.
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One of the conditions is Cancer.
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Which of the following air pollutants is correctly paired with one of its major effects?
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Response:

The accurate choice is;

Sulfur oxides linked to acid precipitation

Details:

Sulfur oxide in the atmosphere interacts with oxygen, water, and other chemicals leading to the creation of acidic precipitation known as acid rain.

Sulfur oxides react with moisture in clouds to generate sulfuric acid as follows;

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3 0
19 days ago
A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
Tems11 [2631]

Answer: The molecular formula will be C_8H_8O_2

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

For O =\frac{1.5}{1.5}=1

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is C_4H_4O

The empirical weight is calculated as C_4H_4O = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula can be derived as=2\times C_4H_4O=C_8H_8O_2

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