A) s o of socl2 (b) t at which the reaction becomes nonspontaneous so3(g) + scl2(l) → socl2(l) + so2(g) δg o rxn = −75.2 kj so3(

The molar mass of C2F4 (tetrafluoroethylene) is 100 g/mol. To find the number of moles of C2F4 in the specified quantity,
n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4
The calculation for the number of molecules per mole is done via the equation,
(0.0585 mols) x (6.022 x 10^23)
Given that each molecule contains 4 F atoms, then,
(0.0585 mols) x (6.022 x 10^23)(4)
= 1.41 x 10^23 atoms of F

Answer:

inspect the packaging

Explanation:

Answer:

The resulting salt is Cesium Carbonate

Explanation:

2CsOH + H2CO3 → Cs2CO3 + 2H2O

Response:

Mole fraction: 0.0157.

Molality: 0.889m

Mass%: 16%

Clarification:

The measurement units are mole fraction, molality, and mass percentage.

Mole fraction is calculated using moles of glucose relative to the total moles present.

The glucose moles for 1L is:

0.944 moles.

The moles of water in 1L are:

1L × (1.0624kg/L) × (1000g / 1kg) × (1mol / 18.02g) = 59.0 moles of water

Mole fraction is given by: 0.944 moles / (59.0 mol + 0.944mol) = 0.0157

Molality is defined as moles of solute (0.944) per kilogram of solution (1.0624kg):0.944mol / 1.0624kg =

0.889m

For mass percentage, the total mass equals 1062.4g, and the mass of 0.944 moles of glucose is:

0.944mol×(180.156g/1mol) = 170g of glucose. Mass%:

170g / 1062.4g ×100 = 16%

I trust this information is useful!

To find the number of particles, use the formula: 2.0 g multiplied by (6.0 x 10^23 particles per mol) divided by 20.18 g/mol. Thus, Option C is accurate.