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Ksju
1 month ago
12

Which type of energy in gasoline is transformed into mechanical energy and a motorcycle engine

Chemistry
1 answer:
KiRa [2.9K]1 month ago
7 0
The "Chemical Energy" present in gasoline is converted into mechanical energy within a motorcycle engine. Hope this assists!
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compute the mass of CaSO4 that can be prepared by the reaction of 3.2900g of H2SO4 with 3.1660g of CaCO3
alisha [2963]
<span>4.3065 g To begin with, consult the atomic masses for each involved element. Atomic weight of Calcium = 40.078 Atomic weight of Carbon = 12.0107 Atomic weight of Hydrogen = 1.00794 Atomic weight of Oxygen = 15.999 Atomic weight of Sulfur = 32.065 Next, compute the molar masses of both reactants and the product. Molar mass H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass CaCO3 = 40.078 + 12.0107 + 3 * 15.999 = 100.0857 g/mol Molar mass CaSO4 = 40.078 + 32.065 + 4 * 15.999 = 136.139 g/mol The balanced equation for the reaction between H2SO4 and CaCO3 is: CaCO3 + H2SO4 ==> CaSO4 + H2O + CO2 Thus, 1 mole each of CaCO3 and H2SO4 is necessary to generate 1 mole of CaSO4. Let's check the amount of moles we have for CaCO3 and H2SO4. CaCO3: 3.1660 g / 100.0857 g/mol = 0.031632891 mol H2SO4: 3.2900 g / 98.07688 g/mol = 0.033545113 mol H2SO4 is in slight excess, therefore CaCO3 is the limiting reactant, suggesting we can expect 0.031632891 moles of product. To find the mass, multiply the number of moles by the molar mass calculated previously. 0.031632891 mol * 136.139 g/mol = 4.306470148 g Given that we have 5 significant figures from our data, we round the final result to 5 figures, yielding 4.3065 g</span>
8 0
1 month ago
Read 2 more answers
When the concentration of solute in a solid solution exceeds its solubility limit, a new solid solution or phase forms that has
eduard [2782]
The answer is true. A solid solution consists of a solid state solution formed by one or more solutes dissolved in a solvent, or a combination of two crystalline solids that coexist within a crystal lattice. Metal alloys, semiconductors, and moist solids are examples of such solid solutions.
8 0
2 months ago
How many liters of cane juice is needed to supply 5g sucrose if cane juice contains 12% sucrose
alisha [2963]

Given parameters:

Mass of sucrose  = 5g

Density of sucrose  = 1.12g/mL

Percentage of sucrose per liter of cane juice  = 12%

Unknown:

Volume of cane juice required =?

We need to understand the relationship between volume and density. Density represents mass per unit volume.

Mathematically;

                Density  = \frac{mass}{volume}

Now, calculate the volume of sucrose;

                  1.12g/mL = \frac{5}{Volume}

       Volume  = \frac{5}{1.12}    =  4.46mL   = 4.46 x 10⁻³L since 1000mL  = 1L

Since 12% of one liter of cane juice is sucrose,  

                    12% of  x  liter of cane juice  = 4.46 x 10⁻³L

                   Volume of cane juice  = 4.46 x 10⁻³ x \frac{100}{12}   = 0.037L

Volume of cane juice needed is  0.037L

   

6 0
2 months ago
Which statement is true about writing chemical formulas of covalent compounds?
VMariaS [2998]
d is your answer; I hope this assists you.
4 0
2 months ago
Read 2 more answers
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