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Anastaziya
3 days ago
9

Explain using the particles theory what happens when steam in the bathroom hits a cold surface such as a mirror

Chemistry
1 answer:
eduard [2.6K]3 days ago
5 0
<span>The condensation on the mirror occurs when water vapor contacts a chillier surface. When you let cold water run, the surroundings become cooler. Consequently, the steam generated from the hot shower primarily condenses nearby and doesn’t reach the mirror.</span>
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A solution is prepared by adding 100 mL of 1.0 M HC2H3O2 (aq) to 100 mL of 1.0 M NaC2H3O2 (aq). The solution is stirred and its
KiRa [2857]
The correct equation is (C) H3O+(aq) + C2H3O2−(aq) -> HC2H3O2(aq) + H2O(l). A buffer system is composed of a weak acid and its corresponding salt, effectively stabilizing the pH levels within a solution. The buffer works by adjusting the concentrations of the conjugate acid and base, maintaining the pH constant.
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5 days ago
Bonds between two atoms that are equally electronegative are _____. bonds between two atoms that are equally electronegative are
Alekssandra [2891]
When two atoms with equal electronegativity bond together, they form nonpolar covalent bonds.

Your second statement mirrors the first; the second statement likely reads, "Bonds between two atoms with unequal electronegativity are termed polar covalent bonds."
4 0
1 month ago
Does Na2 gas posses metallic character? Explain your answer..​
alisha [2865]

Clarification:

The Na2 molecules comprise atoms that are connected by a purely covalent bond since both atoms have the same electronegativity.

Metallic bonding only manifests when several atoms cluster together. Such aggregates may not tend to be stable, as larger masses of material typically exhibit greater stability thermodynamically. Therefore, they often merge until a significant metal chunk is formed.

In some ways, metallic bonding can be considered a variant of covalent bonding, but it is more communal—delocalized across numerous atoms—and electron deficient (there are more energy states than available electrons, which contributes to conductive traits). This implies that the term “metallic bond” might appear contradictory, akin to referring to a forest with a single tree.

Engage me in comments

4 0
1 month ago
Name one manufactured device or natural phenomenon that emits electromagnetic radiation in each of the following wavelengths: ra
alisha [2865]
Radio - A radio station sends out radio waves that are received by a radio receiver.
<span>Microwaves - A microwave oven heats food using microwave radiation.</span>

<span>Infrared - Infrared light is utilized by TV remotes to send signals to a sensor on the TV, enabling functions like volume adjustment and channel selection.</span>

<span>Visible light - Comes from sunlight or light bulbs.</span>

<span>Ultraviolet - UV lamps are used for tanning and for verifying the authenticity of currency.</span>

<span>X-rays - Machines for chest X-rays and backscatter X-ray scanners for airport security utilize X-rays.
</span>
Gamma rays - <span>Gamma rays are utilized in medical instruments for eliminating cancer cells and for sterilizing medical supplies.</span>
7 0
1 month ago
Be sure to answer all parts. The sulfate ion can be represented with four S―O bonds or with two S―O and two S═O bonds. (a) Which
Anarel [2728]

Response:

a) Representation - (in attachment)

b) The geometry is tetrahedral

c) sp^{3} hybrid orbitals involve sigma bonding.

\pi orbitals arise from the overlap of sulfur's d-orbitals with the p-orbitals of oxygen.

Clarification:

a)

Representation in attachment.

The total charge in both structures is -2. Structure (b) is preferred according to the resonance forms since the formal charges within the species are preserved.

Thus, structure (b) represents the sulfate ion more accurately.

b) In the sulfate ion, the sulfur atom forms connections with four distinct oxygen atoms. Using VSEPR theory, the sulfate ion is tetrahedral in shape.

There are four sigma bonds and no lone pairs surrounding the central atom.

Consequently, the sulfur atom's hybridization is sp^{3}

c)

The s and p orbitals of sulfur undergo hybridization to form sigma bonds. The orbitals involved in \pi bonding are

Therefore, \pi bonds result from the overlapping of sulfur's d-orbitals with the p-orbitals of oxygen.

5 0
25 days ago
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