Explain using the particles theory what happens when steam in the bathroom hits a cold surface such as a mirror

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

• The solution's volume is 350 mL
• The solution's molarity is 2.75 M
• The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

Answer: Option (a) is the correct answer.

Explanation:

Under conditions of low pressure and high temperature, gas molecules exhibit negligible attractions or repulsions among themselves. Hence, gases behave ideally in these scenarios.

Conversely, at low temperatures, there is a reduction in the kinetic energy of gas molecules, while high pressure compels the molecules to be closer together.

Thus, attractive forces emerge between molecules in conditions of low temperature and high pressure, causing gases to be termed real gases.

Therefore, we conclude that the ideal gas law becomes less accurate when pressure increases and temperature decreases.

The amount of heat needed to elevate an object's temperature can be determined using the formula,
heat = mass x specific heat x (T2 - T1)
Thus, specific heat can be found with the following formula,
specific heat = heat / (mass x (T2 - T1))
By substituting,
specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The calculated specific heat from the above equation is 0.838 J/g°C. 

Answer:

Here is an explanation related to the same question.

Explanation:

• According to Le Chatelier's principle , when the balance of a system is disturbed by external changes, the system adapts by altering the concentrations of its components in a manner that counteracts the disturbance, thus achieving a new stable equilibrium of concentration that differs from its previous state.
• Bromothymol blue is known to function as a phenolic compound that operates effectively as an acid in water solutions. Because it is classified as a weak acid, it should not react rapidly, while simultaneously establishing equilibrium with its largely unrelated form.

For such a weak diprotic acid, the typical economic expression can indeed be articulated as:

    ⇒  

• It can be ultimately shown through Le Chatelier's concept that when a strong acid is introduced, the complete disorientation of either component influences an increase in the proton levels within the medium.
• Likewise, it takes up protons throughout the medium leading to the breakdown of water each time a solution is introduced. Consequently, the concentration of particles in the medium decreases. To adjust for this change, the equilibrium shifts appropriately, thereby prompting further dissociation of the respective acid into its dianion in the presence of protons, aiming to nullify the initial disturbance.

Answer: A= 0.5, B = 0.25, C = 0.125, D = 0.015625 and E = 0.00390625

Explanation:

The half-life of a substance refers to the duration it takes for that substance to decrease to half of its original quantity.

Here, n signifies the count of half-lives.

The remaining quantity of the substance after n half-lives can be determined using the formula provided,

When n = 1,

Fraction of substance remaining = 0.5¹ = 0.5.

This indicates that after the first half-life, the remaining quantity is half of the original amount.

Thus, we find A = 0.5

<pfor n="2," we="" calculate=""><pso after="" two="" half-lives="" the="" remaining="" quantity="" is="" of="" original=""><phence>B = 0.25 <pfor n="3," we="" have=""><pso after="" three="" half-lives="" the="" remaining="" amount="" is="" of="" original.=""><ptherefore we="" find="">C = 0.125<pfor n="6," we="" see="">

Thus, D = 0.015625

<pfor n="8," we="" calculate=""><pconsequently>E = 0.00390625

The calculated values for A, B, C, D, and E are 0.5, 0.25, 0.125, 0.015625, and 0.00390625 respectively.

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