answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmasim
2 months ago
11

Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s pea

k of this element appear to the left of, the right of, or in the same position as the 1s peak of the element in part (a)? Explain your reasoning.

Chemistry
1 answer:
eduard [2.7K]2 months ago
4 0

La pregunta está incompleta. Aquí tienes la pregunta completa.

La espectroscopía de fotoelectrones se muestra a continuación.

(a) Basado en el espectro de fotoelectrones, identifica el elemento desconocido y escribe su configuración electrónica.

(b) Observando el elemento en la tabla periódica que está directamente a la derecha del identificado en el inciso (a). ¿El pico 1s de este elemento aparecería a la izquierda, a la derecha, o en la misma posición que el pico 1s del elemento del inciso (a)? Justifica tu razonamiento.

Respuesta y Explicación: La Espectroscopía de Fotoelectrones es un método para determinar la energía relativa de los electrones en átomos y moléculas.

Se basa en el efecto fotoeléctrico: cuando la radiación energética incide sobre una sustancia, se expulsa un electrón. Si conocemos la energía cinética del electrón expulsado, llamado fotoelectrón, y la energía de la radiación incidente, podemos calcular la energía del electrón en la sustancia.

La energía requerida para expulsar un electrón de la muestra se denomina energía de enlace y, dentro de un átomo, depende de la capa en la que se encuentre el electrón: los electrones de valencia (en la capa exterior) tienen menor energía de enlace; los electrones de núcleo (en la capa más interna) tienen la mayor energía de enlace.

En el gráfico, el eje vertical muestra 5 picos para diferentes energías. El pico más cercano al origen, el primero a la izquierda, corresponde al subshell 1s, ya que están más cerca del núcleo, lo que implica que tienen la mayor energía de enlace.

A medida que avanzamos de izquierda a derecha, observamos:

  • Los picos primero, segundo y cuarto tienen la misma altura;
  • La altura del tercer pico es tres veces mayor que la de los picos primero, segundo y cuarto;
  • El quinto pico es una unidad más alto que el primero, segundo y cuarto;

(a) Esto nos lleva a concluir que la configuración electrónica del elemento es

1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}

que corresponde al fósforo con número atómico 15.

(b) El elemento a la derecha del fósforo es el azufre (S). El pico 1s de azufre aparecería en la misma posición que el pico 1s del fósforo, porque los elementos en la tabla periódica están organizados según ciertas propiedades. Los elementos que están en la misma fila horizontal pertenecen al mismo período, y una de sus características es que tienen la misma cantidad total de capas de electrones.

You might be interested in
A chemist uses 0.25 L of 2.00 M H2SO4 to completely neutralize a 2.00 L of solution of NaOH. The balanced chemical equation of t
Tems11 [2777]
2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O

v(H₂SO₄)=0.25 L
c(H₂SO₄)=2.00 mol/L
v(NaOH)=2.00 L

n(H₂SO₄)=c(H₂SO₄)v(H₂SO₄)
n(NaOH)=2n(H₂SO₄)=2c(H₂SO₄)v(H₂SO₄)

c(NaOH)=n(NaOH)/v(NaOH)=2c(H₂SO₄)v(H₂SO₄)/v(NaOH)

c(NaOH)=2*2.00*0.25/2.00=0.5 mol/L

the concentration of the NaOH solution is 0.5 mol/L
5 0
1 month ago
Read 2 more answers
A research balloon at ground level contains 12 L of helium (He) at a pressure of 725mmHg and a temperature of 30.00∘C. When the
eduard [2782]
The resulting temperature, following the change in volume and pressure, is -27.26°C. To find this temperature, we apply the combined gas law equation—a formulation where initial and final pressures, volumes, and temperatures are compared. Given the initial conditions and transformations, when we input the stipulated values, we reach the conclusion that the resultant temperature is -27.26°C.
5 0
23 days ago
A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state.Th
castortr0y [3046]
The answer is C. The specific amount of energy released when excited electrons fall back to the ground state produces an emission spectrum. That energy is emitted as photons with precise wavelengths corresponding to the energy differences between levels. Because each element yields a characteristic set of wavelengths, the emission spectrum can be used to identify the element in the sample.
5 0
29 days ago
Read 2 more answers
The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the
Alekssandra [3086]

Answer:

Mitochondria are plentiful in mammalian cells, with their proportions varying across different tissues, from less than 1% in white blood cells to as high as 35% in heart muscle cells. It is essential to understand that mitochondria are not static structures but instead form a dynamic network that frequently undergoes processes of fission and fusion. In skeletal muscle, they exist as part of a reticular membrane network. The two subpopulations, subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria, occupy different subcellular regions and exhibit slight differences in their biochemical and functional characteristics tied to their anatomical context. The SS mitochondria are positioned just beneath the sarcolemma, while IMF mitochondria are found closely associated with myofibrils. Their distinct properties likely play a role in their adaptability. SS mitochondria make up about 10-15% of the total mitochondrial volume and are believed to be more adaptable than their IMF counterparts, despite the latter displaying higher levels of protein synthesis, enzyme activity, and respiration (1).

Explanation:

0 0
2 months ago
Read 2 more answers
Draw the structures of two different compounds that have the composition CH3NO2. All three H atoms must remain bonded to the C a
Tems11 [2777]

Answer:

The configurations are illustrated below.

Explanation:

Hydrogen possesses a single electron in its outer shell, carbon has 4, nitrogen has 5, and oxygen holds 6. To achieve an octet (or duet for hydrogen), they require 1, 4, 3, and 2 electrons respectively.

Therefore, each hydrogen atom will share one electron with carbon, while the remaining electron will be shared with nitrogen, maintaining 4 electrons available for sharing. Carbon can form two bonds with both oxygen atoms, expanding its octet; however, this renders it unstable, leading to the formation of resonance structures (redistribution of electrons), and charge formation. One of the oxygen atoms will share only one electron with nitrogen.

The two structures are depicted below.

3 0
1 month ago
Other questions:
  • A person loses 2.70 lbs in two weeks how many grams did he lose?
    6·2 answers
  • How many carbon atoms are there in a 1.3-carat diamond? diamonds are a form of pure carbon. (1 carat?
    13·2 answers
  • Convert 3.8 Km/sec to miles/year
    12·1 answer
  • For the chemical reaction HCN ( aq ) + KOH ( aq ) ⟶ H 2 O ( l ) + KCN ( aq ) HCN(aq)+KOH(aq)⟶H2O(l)+KCN(aq) write the net ionic
    8·1 answer
  • A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
    7·1 answer
  • The maximum acceptable concentration of fluoride in tap water is 1.5mg/L. Express this concentration in ppm. Then figure what vo
    13·1 answer
  • The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear
    11·1 answer
  • Write the complete balanced equation for the neutralization reaction that occurs when aqueous hydroiodic acid, HI, and sodium hy
    14·1 answer
  • Determinación de pH Expresa las siguientes concentraciones de [H+ ] en función del pH • [H+] = 0.001 M • [H+] = 0.002 M • [H+] =
    11·1 answer
  • Draw a structure for the product of nucleophilic substitution obtained on solvolysis of tert−butyl bromide in methanol, and arra
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!