How many moles are equal to 89.23 g of calcium oxide?

Answer: The amount of moles equivalent to 89.23 g of calcium oxide is 1.593 moles.

Solution:

The provided mass of calcium oxide = 89.23 g

Molar mass of calcium oxide = 56 g/mole

Utilized formula:

Substituting the known values into this equation allows us to find the moles of calcium oxide.

Thus, 1.593 moles correspond to 89.23 g of calcium oxide.

The chemical representation of calcium oxide is CaO.
The molar mass of CaO is calculated as 40 + 16, resulting in 56 g/mol.
Thus, one mole has a mass of 56 grams.
Consequently, 56 grams of CaO corresponds to one mole.
Hence, by taking 89.23 grams, we find it equals - 1/56 multiplied by 89.23, which gives approximately 1.6 moles of CaO.