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kirza4
1 month ago
10

4. We have 4 identical strain gauges of the same initial resistance (R) and the same gauge factor (GF). They will be used as R1,

R2, R3, and R4 in a Wheatstone bridge. We want to measure the tensile strain of a rod subjected to a tensile force. What is the maximum bridge constant (kappa) that we can reach
Physics
1 answer:
Softa [3K]1 month ago
3 0
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A book rests on the shelf of a bookcase. The reaction force to the force of gravity acting on the book is 1. The force of the sh
serg [3582]

Answer:

1. The force applied by the shelf supporting the book.

Explanation:

The free body diagram for the book is represented as follows:

1 - The weight of the book acting downward

2 - The normal force exerted by the shelf upward on the book.

As the book remains stationary, these two forces balance each other, and in accordance with Newton's Third Law, the reactive force equivalent to gravity is opposite and equal to the weight of the book. This reaction force prevents the book from falling off the shelf.

6 0
2 months ago
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A suspension system is being designed for a 1300 kg vehicle. When the vehicle is empty, its static deflection is measured as 2.5
Keith_Richards [3271]

Answer: damping coefficient = 1.5×10^5Ns/m

Explanation:

Refer to the attached file for the solution

3 0
1 month ago
A new moon is discovered orbiting Neptune with an orbital speed of 9.3 103 m/s. Neptune's mass is 1.0 1026 kg. What is the
Yuliya22 [3333]
The radius of the moon's orbit is calculated as R = 7.715 x 10⁷ m, and the moon's orbital period is T = 14.48 hr. The given orbital speed of the moon is v = 9.3 x 10³ m/s, with Neptune's mass being M = 1.0 x 10²⁶ Kg. The moon's orbital velocity can be expressed using the formula. Therefore, by squaring the equation and resolving for r + h, we calculate: R = GM / v². Upon substituting in, we find R to be 7.715 x 10⁷ m. The relation for the moon's orbital period yields T = 2π/ω and simplistically, T = 2πR/v, where ω = v/r. Following this, we compute T, leading to the conclusion: T = 14.48 hr.
3 0
1 month ago
Two satellites, X and Y, are orbiting Earth. Satellite X is 1.2 × 106 m from Earth, and Satellite Y is 1.9 × 105 m from Earth. W
Yuliya22 [3333]
Satellite X exhibits both a longer period and a reduced tangential speed compared to Satellite Y.
4 0
1 month ago
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Observe: Up until now, all the problems you have solved have involved converting only one unit. However, some conversion problem
Softa [3030]

Response:

It is important to note that for units like time and angles, the transformations aren't based on ten, as shown below:

        60 s = 1 min

        60 min = 1 h

        24 h = 1 day

Hence, for this conversion, special attention is needed

the length conversion is based on ten

Clarification:

In numerous problems, the units utilized undergo transformations via equations into alternate units referred to as derived units, and the transformation of these derived units generally results from the multiplication of the transformations of the basic units.

For instance, in the context of velocity, its derived unit is expressed as m / s; therefore, the transformation operates similarly to that of length and time, meaning if they are multiplied in the equation, it continues to be multiplied, and if divided, it remains divided.

It is important to note that for units like time and angles, the transformations aren't based on ten, as shown below:

        60 s = 1 min

        60 min = 1 h

        24 h = 1 day

Hence, for this conversion, special attention is needed

the length conversion is based on ten

      1000 m = 1 km

7 0
1 month ago
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