Answer:
The car that is the furthest from the finish line is: Car III (Choice C).
Explanation:
Here, we seek the car with the lowest overall average speed throughout the race. Thus, the one in last place inherently possesses the slowest average speed.
Since Car III is significantly behind Cars I and II, Choice A and B cannot be correct. Choice D is also not valid, as the positions of the cars are not the same. Lastly, Choice E is incorrect due to sufficient evidence demonstrating that Choice C has the lowest average speed.
Calculating the average speed is straightforward by using the formula involving distance and time:
average speed = distance / time
Thus, we have:
average speed = 4875 ft / 6.85 minutes
<span>average speed = 711.68 ft / min</span>
Answer:900 feet
Explanation:
Given
Velocity 
It takes 100 feet to come to a stop.
Utilizing the equation of motion
Where
v,u=Final and initial velocities
a=acceleration
s=distance traveled
When the speed is 60 mph 
s=900.08 feet
Part a) The package's speed matches the helicopter's speed in the horizontal direction. Thus, after a time "t", the horizontal velocity remains constant, while in the Y-direction, it begins to fall under gravity. Part b) The distance relative to the helicopter is equivalent to the distance it falls freely. Part c) If the helicopter is ascending uniformly, the package's final speed after time t can be described in terms of its initial speed and gravity.
Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper): 150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers):?
The principle of momentum conservation indicates that the momentum before impacts equals the momentum after impacts. This can be represented mathematically as:
Pa= Pb
Pa symbolizes the momentum prior to collision and Pb refers to momentum after collision.
Applying this principle to the aforementioned scenario results in:
Momentum pre-collision= momentum post-collision.
Momentum pre-collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum post-collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
We now know that Momentum pre-collision equals momentum post-collision.
<presulting in="">
1215 = 555 v2
v2 = 2.188 m/s
Consequently, the final velocity of the combined bumper cars is 2.188 m/s
</presulting>
