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Sladkaya
1 month ago
12

Q1) A vapor-compression refrigeration system operates on the cycle of Fig. 9.1. The refrigerant is 1,1,1,2-Tetrafluoroethane. Gi

ven that the evaporation T = 4°C, the condensation T = 34°C, η(compressor) = 0.76, and the refrigeration rate = 1200 kJ⋅s−1, determine the circulation rate of the refrigerant, the heat-transfer rate in the condenser, the power requirement, the coefficient of performance of the cycle, and the coefficient of performance of a Carnot refrigeration cycle operating
between the same temperature levels.
Chemistry
1 answer:
alisha [2.9K]1 month ago
4 0

Answer:

i)   0.5071 kg/s

ii)  -1407.1 kJ/kg

iii)  204.05 kW

iv)  5.881

v)    9.238

Explanation:

Given Data:

evaporation temperature (T) = 4°C = 277.15 K

Condensation Temperature (T) = 34°C = 307.15 K

n (compressor efficiency) = 0.76

refrigeration rate = 1200 kJ/s

i) to find the circulation rate of the refrigerant

m = \frac{Q}{H2 - H1}  = \frac{Q}{H2 - H4\\}  ------- 1

Q = 1200 kJ/s

H2 = entropy at step 2 = 2508.9 (kJ/kg) (obtained from Table F)

H4 = entropy at step 4 = 142.4 (kJ/kg)

back to equation 1

m (circulation rate of refrigerant) = 0.5071 kg/s

ii) heat transfer rate in the condenser

Q = m (H4 - H3)

    = 0.5071 (142.4 - 2911.27)

    = -1407.1 kJ/kg

where H3 = H2 + ΔH23 = 2911.27 (kJ/kg) (as calculated)

iii) power requirement

w = m * ΔH23

   = 0.5071 (kg/s) * 402.37 (kJ/kg) =  204.05 kW

where: ΔH23 = \frac{H'3 - H2 }{0.76} = \frac{2814.7-2508.9}{0.76} = 402.37 (kJ/kg)

iv) coefficient of performance of a cycle

W = Qc / w

  = 1200 kJ/s / 204.05 kW

  = 5.881

v) coefficient of performance of a Carnot refrigeration cycle

w_{carnot} = \frac{T2}{T4 - T2}

            =  277.15 / (307.15 - 277.15)

            = 9.238

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