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2 months ago

A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the distance the car travels during this time.

Physics

2 answers:

Maru [3.3K]2 months ago

6 0

It covered a distance of 39.6 meters.

ValentinkaMS [3.4K]2 months ago

3 0

Answer:

The total distance the car covers is 21.56 meters.

Explanation:

Given that the car starts from rest (initial speed, u = 0), accelerates to 6.6 m/s (final speed, v), over a period of 6.5 seconds (time, t), we first compute the acceleration using the motion formulas.

$v=u+at$

$6.6=0+a\times 6.5$

$a=1.01\ m/s^2$

Next, apply the third equation of motion to calculate distance (s):

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{(6.6)^2}{2\times 1.01}$

Calculating gives s = 21.56 meters.

Therefore, the car travels 21.56 meters within 6.5 seconds, which is the answer you need.

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Answer:

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$\displaystyle y=1.5+(11.29)(1.505)-\frac{9.8(1.505)^2}{2}$

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