answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol13
1 month ago
6

23. While sliding a couch across a floor, Andrea and Jennifer exert forces F → A and F → J on the couch. Andrea’s force is due n

orth with a magnitude of 130.0 N and Jennifer’s force is 32° east of north with a magnitude of 180.0 N. (a) Find the net force in component form. (b) Find the magnitude and direction of the net force. (c) If Andrea and Jennifer’s housemates, David and Stephanie, disagree with the move and want to prevent its relocation, with what combined force F → DS should they push so that the couch does not move?
Physics
1 answer:
Softa [3K]1 month ago
4 0

Response:

a) (95.4 i^ + 282.6 j^) N, b) 298.27 N 71.3º and c) F' = 298.27 N θ = 251.4º

Justification:

a) Using trigonometric functions, we can resolve Jennifer's force

sin θ = Fjy / Fj

cos θ = Fjx / Fj

Calculating the angle, which is 32º to the east of north, taken from the positive x-axis:

T = 90 -32 = 58º

Fjy = Fj sin 58

Fjx = FJ cos 58

Fjx = 180 cos 58 = 95.4 N

Fjy = 180 sin 58 = 152.6 N

Andrea's exerted force is

Fa = 130.0 j ^

Summing forces across both axes:

X axis

Fx = Fjx

Fx = 95.4 N

Y axis

Fy = Fjy + Fa

Fy = 152.6 + 130

Fy = 282.6 N

F = (95.4 i ^ + 282.6 j ^) N

b) Now let's employ the Pythagorean theorem and trigonometry

F² = Fx² + Fy²

F = √ (95.4² + 282.6²)

F = √ (88963)

F = 298.27 N

tan θ = Fy / Fx

θ = tan-1 (282.6 / 95.4)

θ = tan-1 (2.962)

θ = 71.3º

c) To counteract the motion, they must apply an opposing force of equal intensity:

F' = 298.27 N

θ' = 180 + 71.3

θ = 251.4º

You might be interested in
Can a small child play with fat child on the seesaw?Explain how?
inna [3103]
Yes, a small child can indeed play with a heavier child on a seesaw. This is because reducing the distance from the fulcrum for the heavier child increases the effort required, allowing the smaller child to play without much strain.
8 0
1 month ago
Read 2 more answers
When a test charge q0 = 2 nC is placed at the origin, it experiences a force of 8 times 10-4 N in the positive y direction. What
Softa [3030]

Answer:

Electric field, E=4\times 10^5\ N/C

Explanation:

The following values are provided:

Magnitude of charge, q_o=2\ nC=2\times 10^{-9}\ C

Force experienced, F=8\times 10^{-4}\ N

To determine the electric field at the origin, the formula employed is:

F=q_o\times E

E=\dfrac{F}{q_o}

E=\dfrac{8\times 10^{-4}}{2\times 10^{-9}}

E=4\times 10^5\ N/C

Consequently, the electric field at the origin is 4\times 10^5\ N/C. Hence, this provides the sought solution.

3 0
15 days ago
On the assumption that copper– nickel alloys are random mixtures of copper and nickel atoms, calculate the mass of copper which,
inna [3103]

Response:

65.14 g

Clarification:

The entropy change resulting from mixing two metals is

\delta S= R[(n_{cu}+n_{Ni})ln(n_{cu}+n_{Ni})-n_{cu}lnn_{cu}-n_{Ni}lnn_{Ni}]

Here, R is the real gas constant, n_{cu} denotes the moles of copper, while n_{Ni} signifies the moles of nickel.

Therefore, determining the moles of Nickel yields

n_{Ni}=\frac{m_{Ni}}{M_{Ni}}

n_{Ni}=\frac{100}{58.69} =1.7 moles

Then substituting n_{Ni} = 1.7 into the equation produces ΔS= 15,

with R= 8.314, and solving gives

15= R[(n_{cu}+1.7)ln(n_{cu}+1.7)-n_{cu}lnn_{cu}-1.7ln1.7]

Upon resolving, the quantity of moles of copper in the mixture equals

n_cu= 1.025

Thus, the copper mass is calculated as n_cu×M_cu = 1.025×63.55 = 65.14 g

Consequently, the required mass is found to be = 65.14 g

3 0
1 month ago
A 1.0 kg brick falls off a ledge of height 44m and lands on the ground at 3.0 s later.
Keith_Richards [3271]
vf^2 = 2ad
vf^2 = 2(9.81)(44m)
vf^2 = 863.28
vf = √863.28
vf = 29.4  - using equations of motion

ME = PE + KE
ME = mgh + 1/2mv^2
ME = (1)(9.81)(44) + 1/2(1)(3^2)
ME = 431.64 + 4.5
ME = 436.14 - applying the principle of energy conservation

hope this helps:)
7 0
29 days ago
A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho
Softa [3030]

The alteration in kinetic energy is \Delta K = 3Fd

Clarification:

According to the work-energy principle, the task performed on an object corresponds to the alteration in its kinetic energy. In mathematical terms:

W=K_f -K_i= \Delta K

where:

W signifies the work performed on the object

K_f denotes the kinetic energy at the end

K_i indicates the kinetic energy at the start

Furthermore, when the force is exerted in line with the object’s motion, the work done is expressed as:

W=F\Delta x

Here,

F represents the force’s magnitude

\Delta x denotes the object’s displacement

In this scenario, the force impacting the object is

F

While the distance moved is the horizontal length traveled, hence

\Delta x = 3d

Consequently, the work accomplished is

W=(F)(3d)=3Fd

Thus, the alteration in kinetic energy amounts to

\Delta K = 3Fd

Learn more about work and kinetic energy:

5 0
1 month ago
Other questions:
  • A 250-kg crate is on a rough ramp, inclined at 30° above the horizontal. The coefficient of kinetic friction between the crate a
    15·2 answers
  • Students work together during an experiment about Newton’s laws. The students use a setup that consists of a cart of known mass
    12·1 answer
  • Fighter jet starting from airbase A flies 300 km east , then 350 km at 30° west of north and then 150km north to arrive finally
    11·1 answer
  • Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 65
    14·1 answer
  • A shell is launched with a velocity of 100 m/s at an angle of 30.0° above horizontal from a point on a cliff 50.0 m above a leve
    13·1 answer
  • According to Newton's Law of Universal Gravitation, which of the following would cause the attractive force between a planet and
    8·1 answer
  • On a foggy day, you are driving at 70 mph and Granny is driving at 50 mph. As you try to pass her, you both see an overturned tr
    9·1 answer
  • Using the formula for kinetic energy of a moving particle k=12mv2, find the kinetic energy ka of particle a and the kinetic ener
    14·1 answer
  • The air in tires can support a car because gases __________.
    5·1 answer
  • An 8.0-kg history textbook is placed on a 1.25-m high desk. How large is the gravitational potential energy of the textbook-Eart
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!