A wire of 5.8m long, 2mm diameter carries 750ma current when 22mv potential difference is applied at its ends. if drift speed of

Answer:

More than 48%

Explanation:

If the interest is calculated monthly based on the outstanding balance, it leads to an effective annual rate of...

(1 + 4%)^12 - 1 = 60.1%... more than 48%

Let T be the force exerted on the rope by her. This force induces tension in the rope, which exerts an upward force on the crates, while the weight of the crate pulls downward. Thus, the net force acting on the crate can be expressed as mg - T, acting in the downward direction. According to Newton's law, we can set up the equation: mg - T = ma. Given that a = 0 (the speed remains constant), this simplifies our equation to mg - T = 0, which leads to T = mg. Therefore, T = 25 x 9.8 = 245 N, indicating that the force she needs to apply is 245 N.

<span>First, apply Newton's second law of motion: F = ma. Force equals mass times acceleration. This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time, we have force = (mass * velocity) / time, leading us to conclude that (mass * velocity) / time will equal momentum / time. Hence, we derive the equation mass * velocity = momentum. Momentum = mass * velocity. For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s, Momentum = 6300 * 0.11, resulting in P = 693 kg (m/s). For the dolphin, having a mass of 50 kg and moving at 10.4 m/s, Momentum = 50 * 10.4, yielding P = 520 kg (m/s). Thus, the elephant has a greater momentum (P) due to its larger size.</span>

Answer:

 a

    The density of volume charge is  

b

    The density of surface charge is  

Explanation:

The question states that

    The radius measures  R

     The length is L

       The speed is  v

        The ion count per unit volume is  n

         The charge per ion is  q

          The surface thickness of the cylinder is  

The volume charge density is mathematically expressed as

     

The surface charge density is mathematically expressed as

   

substituting for  

     

     

Answer:

The time required is 20 μs

Explanation:

Here is the data provided:

temperature = 20°C  = 293 K

radius = 1 cm

atomic mass of air = 29 u

To determine

the duration for air to refill the vacuum space

solution:

We calculate the root mean square velocity of air particles. This can be expressed as:

where m indicates mass, t is temperature, v is speed, and R is the ideal gas constant, which is approximately 8.3145 (kg·m²/s²)/K·mol.

v = ............................1

v =

Resulting in v = 501.99 m/s.

<pNow, to cover the distance of 1 cm,<pThe duration needed for air is calculated as:

time taken =

which gives us:

time taken =

so, time taken = 19.92 × seconds = 20μs.

Thus, the required time is 20 μs.