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Tasya
1 month ago
11

True or False:A retractable service pit cover can help other shop employees from falling into the pit while another technician i

s in the pit servicing a car
Engineering
2 answers:
Kisachek [356]1 month ago
7 0

Answer:

False

Explanation:

grin007 [323]1 month ago
6 0

The assertion that a retractable service pit cover prevents other shop workers from accidentally falling into the pit while a technician is inside servicing a vehicle is true.

Explanation:

This cover effectively stops employees from unintentionally dropping into the inspection pit and simultaneously allows access beneath the vehicle. It operates with ease and can be quickly deployed or retracted, ensuring safety for workers and visitors alike.

The technician can adjust the cover to any desired position, allowing either full or partial exposure of the vehicle for maintenance. It is constructed to support weights up to 200 kg, enabling technicians to stand on it while working on the front or rear of the vehicle.

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Mrrafil [318]

Answer:

An attachment follows below

Explanation:

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If \xi = 0, it is possible to set c = 0 but an inductor will still possess some capacitance.

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1 month ago
The first step to merging is entering the ramp and _____.
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Answer:

D.informing your passengers of your destination

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1 month ago
Let Deterministic Quicksort be the non-randomized Quicksort which takes the first element as a pivot, using the partition routin
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23 days ago
1. You do not need to remove the lead weights inside tires before recycling them.
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1 month ago
The uniform dresser has a weight of 90 lb and rests on a tile floor for which the coefficient of static friction is 0.25. If the
Kisachek [356]

Answer:

a) F = 736.065\,lbf, b) \mu_{k} = 0.15

Explanation:

a) The uniform dresser can be modeled using specific equilibrium equations:

\Sigma F_{x} = F - \mu_{k}\cdot N = 0

\Sigma F_{y} = N-m\cdot g=0

Following some algebraic manipulations, the formulated equation is derived:

F = \mu_{k}\cdot m \cdot g

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b) Similarly, the man can be represented by a set of equilibrium equations:

\Sigma F_{x} = -F + \mu_{k}\cdot N = 0

\Sigma F_{y} = N-m\cdot g=0

After some algebraic changes, the expression for the coefficient of static friction comes out as:

\mu_{k} = \frac{F}{m\cdot g}

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\mu_{k} = 0.15

3 0
23 days ago
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