Impure benzoic acid was dissolved in hot water. the container of solution was placed in an ice-water bath instead of being allow

Graphite exhibits a large covalent structure where each carbon atom is bonded to three carbon atoms via covalent bonds.

Answer:

Mass of Fe = 32.55 g

Explanation:

The molar mass of a single Fe atom is 55.845 g/mol

This means that

1 mole of Fe equals = 55.845 g ..............(1)

According to the mole concept,[ [TAG_24]]

1 mole of Fe contains = atom..........(2)

If we substitute 1 mole in equation (2) with 55.845 g, it becomes:

55.845 g of Fe contains = atoms

Reversing the equation yields

atoms of Fe correspond to 55.845 g

1 atom of Fe corresponds to g

one atom corresponds to

On computation,

one atom corresponds to 32.55 g of Fe

Mass of Fe = 32.55 g

To start, consult the periodic table to pinpoint the element with an average atomic mass of 24.3. The amu is simply the number listed under the element, leading us to conclude that Mg is the answer.

The answer is - 0.138 M. The buffer pH can be determined using the Henderson equation. Here, acts as a weak acid and serves as its corresponding conjugate base. The weak acid has two protons, while the base contains one. The equation can therefore be expressed in terms of protons transferred. Phosphoric acid can donate protons in three stages; the equation we’ve referenced pertains to the second stage, as the acid then has only two protons available and the base only one. Given the concentration of the acid as 0.10 M, we need to calculate the concentration of the base necessary to form a buffer with a pH of exactly 7.0. Substituting the values into the equation leads us to the solution. Cross-multiplying, we find that [base] = 1.38(0.10), yielding [base] = 0.138. Therefore, the concentration of the base needed for the buffer is 0.138 M.

7.35 moles of oxygen. Initially, for each mole of H₂CO₃, there are 3 moles of oxygen, as derived from the acid's formula. For 2.45 moles of the compound stated in the problem, which is carbonic acid, we calculate: If 1 mole of H₂CO₃ corresponds to 3 moles of oxygen, then for 2.45 moles of H₂CO₃, we have X moles of oxygen. Thus, X = (3 × 2.45) / 1 = 7.35 moles of oxygen.