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max2010maxim
1 month ago
5

Why is the atomic mass of iron, 55.845 amu, most similar to the mass of iron-56, yet less than 56 amu? The atomic mass is the si

mple average of the masses of the two most abundant isotopes. Iron‑56 is the most abundant isotope, so the atomic mass of iron is most similar to the mass of iron‑56. The second most abundant isotope is iron‑54, which reduces the atomic mass to less than 56 amu. The atomic mass is the weighted average of the masses of all of the isotopes. Iron‑56 is the most abundant isotope, so the atomic mass of iron is most similar to the mass of iron‑56. The second most abundant isotope is iron‑54, which reduces the atomic mass to less than 56 amu. The atomic mass is the weighted average of the masses of the two most abundant isotopes. Iron‑56 is the most abundant isotope, so the atomic mass of iron is most similar to the mass of iron‑56. The second most abundant isotope is iron‑54, which reduces the atomic mass to less than 56 amu. The atomic mass is the simple average of the masses of all of the isotopes. Iron‑56 is the most abundant isotope, so the atomic mass of iron is most similar to the mass of iron‑56. The second most abundant isotope is iron‑54, which reduces the atomic mass to less than 56 amu.
Chemistry
1 answer:
eduard [2.7K]1 month ago
8 0

Answer:

Iron-56 is the predominant isotope, making the atomic mass of iron closest to that of iron-56.

Explanation:

The isotopic abundance for iron is:

⁵⁴Fe: 5.82%

⁵⁶Fe: 91.66%

⁵⁷Fe: 2.19%

⁵⁸Fe: 0.33%

This indicates that Iron-56 is the most prevalent isotope of iron.

Considering that the atomic mass is derived from the sum of the masses of the isotopes adjusted for their abundance, and given that Iron-56 is the most common isotope, it follows that the atomic mass of Fe is likely to be similar to that of ⁵⁶Fe due to its higher abundance.

The accurate option is:

Iron-56 is the primary isotope, hence the atomic mass of iron aligns closely with the mass of iron-56.

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When drawing the Lewis structure for a molecule, after drawing the skeletal structure and distributing all of the electrons arou
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Answer: Rearrange the lone pairs of electrons from the outer atom(s) to create double or triple bonds with the central atom.

Explanation:

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1 month ago
Modern commercial airliners are largely made of aluminum, a light and strong metal. But the fact that aluminum is cheap enough t
lorasvet [2795]

Respuesta:

Un avión fabricado con aluminio puede transportar una mayor cantidad de pasajeros comparado con uno de acero.

Explicación:

La masa total que el avión es capaz de levantar es:

m_{tot}=m_{fuselage}+m_{passangers}

Para el aluminio:

m_{tot}=m_{fus-Al}+m_{pas-Al}

m_{fus-Al}=\delta _{Al}*V_{fuselage}

y

V_{fuselage}=\frac{\pi *L}{4}*[D^2-(D-e)^2]

donde:

  • L es longitud
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  • e es grosor

m_{tot}=\delta _{Al}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Al}

Para el acero (mismo procedimiento):

m_{tot}=\delta _{Steel}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Steel

Sabiendo que la masa total que el avión puede levantar es constante y que el aluminio tiene una densidad menor que la del acero, podemos afirmar que el avión de aluminio puede levantar un mayor número de pasajeros.

También es posible estimar un peso promedio de los pasajeros para calcular cuántos podría soportar.

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2 months ago
the image above shows a chamber with a fixed volume filled with gas at a pressure of 1560 mmHg and a temperature of 445.0 K. If
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Answer:

The new gas pressure within the chamber registers at 1,093.75 mmHg

Explanation:

The Gay-Lussac Law establishes a relationship between a gas's pressure and temperature when volume remains constant. This principle asserts that gas pressure is directly tied to its temperature: as temperature increases, pressure rises, and conversely, as temperature falls, pressure also diminishes. Therefore, the Gay-Lussac law can be depicted mathematically as:

\frac{P}{T} =k

Given an initial and final state of gas, we can apply the following formula:

\frac{P1}{T1} =\frac{P2}{T2}

In this scenario:

  • P1= 1560 mmHg
  • T1= 445 K
  • P2=?
  • T2= 312 K
<psubstituting:>

\frac{1560 mmHg}{445 K} =\frac{P2}{312 K}

Calculating:

P2=\frac{1560 mmHg}{445 K} *312K

P2=1,093.75 mmHg

The new gas pressure inside the chamber is 1,093.75 mmHg

</psubstituting:>
7 0
2 months ago
How many liters of cane juice is needed to supply 5g sucrose if cane juice contains 12% sucrose
alisha [2963]

Given parameters:

Mass of sucrose  = 5g

Density of sucrose  = 1.12g/mL

Percentage of sucrose per liter of cane juice  = 12%

Unknown:

Volume of cane juice required =?

We need to understand the relationship between volume and density. Density represents mass per unit volume.

Mathematically;

                Density  = \frac{mass}{volume}

Now, calculate the volume of sucrose;

                  1.12g/mL = \frac{5}{Volume}

       Volume  = \frac{5}{1.12}    =  4.46mL   = 4.46 x 10⁻³L since 1000mL  = 1L

Since 12% of one liter of cane juice is sucrose,  

                    12% of  x  liter of cane juice  = 4.46 x 10⁻³L

                   Volume of cane juice  = 4.46 x 10⁻³ x \frac{100}{12}   = 0.037L

Volume of cane juice needed is  0.037L

   

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