Which statement correctly describes the location and charge of the electrons in an atom?

Response: Water molecules migrate from the dilute to the concentrated solution

Clarification:

During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.

Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.

Answer:

2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat

Explanation:

• To balance chemical equations, coefficients are assigned to both reactants and products.
• This yields an equal count of atoms of each element on both sides of the equation.
• Balancing chemical equations ensures compliance with the law of conservation of mass.
• According to this law, the mass of reactants must equal the mass of products, achievable through balancing the equation.
• The application of coefficients 2, 3, 4, 4, 4 allows for an equal balance in the equation.
• Consequently, the balanced equation can be written as:

       2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat

Answer:

             Protons: 19

             Neutrons: 25

             Electrons: 19

Explanation:

Protons:

                   The atomic number determines the number of protons in an atom. Consequently, with Potassium's atomic number being 19, it contains 19 protons.

Neutrons:

                   The formula to find neutrons is:

                           # of Neutrons  =  Atomic Mass - # of Protons

Given:

                                Atomic Mass  =  43

                                # of Protons  =  19

Thus,

                                # of Neutrons  =  43 - 19

                                # of Neutrons  =  24

Electrons:

                                   In a neutral atom, the quantity of electrons matches that of protons. Therefore, a neutral Potassium atom with 19 protons must equally have 19 electrons.

1) Drift velocity:

2. electrons per individual

Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

where

I stands for current

n represents the density of free electrons

indicates the charge of an electron

A signifies the wire's cross-sectional area

The wire's cross-sectional area can be determined as

where r denotes the wire's radius. Thus, the equation transforms to

In this scenario, we have:

I = 8.0 A as the current

indicates the free electron concentration

d = 1.5 mm is the diameter, making the radius

r = 1.5/2 = 0.75 mm =

So, the resulting drift velocity is:

2)

The entire length of the cord is

L = 3.00 m

And the cross-sectional area is

Consequently, the volume of the cord is

(1)

The number of electrons per unit volume is , thus the total electrons in this cord would be

Overall, the Earth's population rounds to 8 billion individuals, equating to

Hence, the number of electrons distributed to each person is:

Respuesta:

0.16 M

Explicación:

Teniendo en cuenta:

O sea,

Dado que:

Para :

Molaridad = 0.200 M

Volumen = 20.0 mL

Convierte mL a L:

1 mL = 10⁻³ L

Entonces, volumen = 20.0×10⁻³ L

Los moles de son:

Moles de = 0.004 moles

Para :

Molaridad = 0.400 M

Volumen = 30.0 mL

Convertimos mL a L:

1 mL = 10⁻³ L

Volumen = 30.0×10⁻³ L

Entonces, los moles de son:

Moles de = 0.012 moles

Según la reacción:

1 mol de reacciona con 1 mol de

Por lo tanto,

0.012 mol de reacciona con 0.012 mol de

Moles disponibles de = 0.004 mol

El reactivo limitante es el que está en menor cantidad, entonces es el limitante (0.004 < 0.012).

La formación del producto depende del reactivo limitante, así que,

1 mol de reacciona con 1 mol de y produce 1 mol de

0.004 mol de reacciona con 0.004 mol de y genera 0.004 mol de

Los moles restantes de son: 0.012 - 0.004 = 0.008 mol

El volumen total es 20 + 30 mL = 50 mL = 0.050 L

Por lo que la concentración del ion bario, , después de la reacción es: