Suppose you need 7.0m of Grade 70 tow chain, which has a diameter of /38" and weighs 2.16/kgm, to tow a car. How would you calcu

Response:

The resistivity can be expressed as

Clarification:

According to the information provided,

    The value of the electric field measures  

     The density of current is given as  

Typically, resistivity is represented in mathematical terms as

         

by inserting values

       

       

Answer:

35.79 meters

Explanation:

We have an archer, and there is a target. Denote the distance between them as d.

The bowman releases the arrow, which travels the distance d at a velocity of 40 m/s until it hits the target. We establish the equation as:

Right after this, the arrow produces a muffled noise, traveling the same distance d at a speed of 340 m/s in time . Thus, we can derive:

.

Consequently, the sound reaches the archer, precisely 1 second post-firing the bow, resulting in:

.

Using this relationship in the distance formula for sound allows us to write:

.

Substituting the value of d from the first equation yields:

.

Now, after some calculations, we can proceed further:

.

Finally, the value is inserted into the initial equation:

The answer is letter d, 8.3.

 

Here’s a solution for the given problem:

 

We have:

B = 6i - 8j 

Let A be unknown; we'll denote A as = mi + nj 

The resultant A+B lies along the x-axis (which implies A+B = Ki + 0j, where K is yet to be determined,

 

and we also know the magnitude of A+B is equivalent to the magnitude of A,

 

therefore, mag(A+B)=K=sqrt(m^2+n^2), or K^2 = m^2+n^2. 

Using vector addition, A+B becomes (m+6)i + (n-8)j.

 

Since we know A+B = Ki + 0j, we can establish that: 

m + 6 = K 

n - 8 = 0, which gives n=8. 

Thus, K^2=m^2+n^2 means (m+6)^2 = m^2 +8^2 

= m^2 + 12m + 36 = m^2 + 64 

which gives us 12m = 28 

m = 2.33333... 

Consequently, the magnitude of A is sqrt[(2.333...)^2 + 8^2] = 8.3333.

Answer:

Option b. it has the same position and the same acceleration as A

Explanation:

Now, let's examine each statement:

a. it has the same position and the same velocity as A

At the moment B overtakes A, they share the same location. However, their velocities cannot match, or else ball B wouldn't be able to pass ball A. Thus, this statement is false.

b. it has the same position and the same acceleration as A

As established before, their positions coincide, and both balls are subjected to gravitational acceleration, making this statement true.

c. it has the same velocity and the same acceleration as A

While the accelerations are identical, their velocities differ, rendering this statement false.

d. it has the same displacement and the same velocity as A

Though they have traveled the same distance, their velocities are not the same, thus this statement is false.

e. it has the same position, displacement and velocity as A

While their position and displacement match, their velocities do not, so this statement is false.

Therefore, only option b is correct.

The second question necessitates a figure to provide an answer. For the initial question
The acceleration of the sack is
1.5² - 0² = 2a(0.2)
a = 5.63 m/s²
The ramp's reaction force is
F = 8 kg (5.63 m/s²)
F = 45 N
Differentiate the kinematic equation with respect to time to find the velocity's rate of increase.