Answer:
The initially bent young tree has been straightened by adjusting the tensions of the three guy wires to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Please calculate the force and moment reactions at the trunk's base point O, disregarding the weight of the tree.
C and D are situated 3.1' from the y-axis, while B and C are located 5.4' from the x-axis, and A has a height of 5.2'.
Explanation:
Refer to the attached image.
Answer:
The period of the pendulum measuring 16 m is double that of the 4 m pendulum.
Explanation:
Recall that the period (T) of a pendulum with length (L) is defined by:
where "g" denotes the local gravitational acceleration.
Since both pendulums are positioned at the same location, the value of "g" will be consistent for both, and when we compare the periods, we find:
Thus, the duration of the 16 m pendulum is two times that of the 4 m one.
Answer:
b = 0.6487 kg / s
Explanation:
In the context of oscillatory motion, friction is related to velocity,
fr = - b v
where b represents the friction coefficient.
Upon solving the equation, the angular velocity is represented as
w² = k / m - (b / 2m)²
In this case, we're given an angular frequency w = 1Hz, the mass m = 0.1 kg, and the spring constant k = 5 N / m. This allows us to derive the friction coefficient.
Let’s denote
w₀² = k / m
w² = w₀² - b² / 4m²
b² = (w₀² -w²) 4 m²
Now, let's calculate the angular frequencies.
w₀² = 5 / 0.1
w₀² = 50
w = 2π f
w = 2π 1
w = 6.2832 rad / s
Substituting values yields
b² = (50 - 6.2832²) 4 0.1²
b = √ 0.42086
b = 0.6487 kg / s
The speed is V=27.24 m/s.
We need to utilize the linear momentum conservation principle:
The eagle's speed can be defined via two components:
Since speed is a scalar quantity.
Calculating the average speed is straightforward by using the formula involving distance and time:
average speed = distance / time
Thus, we have:
average speed = 4875 ft / 6.85 minutes
<span>average speed = 711.68 ft / min</span>
