684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
The mass of KBr required is 16.7 g. This concludes from a volume of 0.400 L and a concentration of 0.350 M. Utilizing the molarity formula, moles are calculated as 0.14, leading to a molecular weight calculation of 119 g/mol, thus resulting in a mass of 16.7 g of KBr.
-470,809 m is expressed in whole numbers
Given constant pressure, Charles' Law applies to determine the volume using the relationship \dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}. The initial volume V₁ is unknown, T₁ is 450 K, V₂ is 103.4 L, and T₂ is 284.9 K.
