Answer: 24.24 m
Explanation:
A player launches a football 50.0 m at an angle of 61° to the north of west. We will break this down into vertical and horizontal elements.
Horizontal component: 50 cos 61° = 24.24 m directed westward
Vertical component: 50 sin 61° = 43.73 m directed toward the north.
Refer to the diagram below.
Therefore, the westward displacement of the football corresponds to the horizontal component of the displacement, which is 24.24 m.
a) Average velocity: 2.8 m/s
b) Average velocity: 5.2 m/s
c) Average velocity: 7.6 m/s
Explanation:
a)
The car's position over time t can be described by
where
To find the average velocity, we divide the displacement by the elapsed time:
At time t = 0, the position is:
At time t = 2.00 s, the position is:
This leads us to the displacement of
The duration for this interval is
Therefore, the average velocity during this period is
b)
At time t = 0, the position is:
At time t = 4.00 s, the position is:
Thus, the displacement is
The time interval is
This yields an average velocity of
c)
The position at t = 2 s is:
And at t = 4 s it is:
This gives us a displacement of
While the time interval is
So the resulting average velocity is
Find out more about average velocity:
Answer:
The rotational angular speed is measured at 1.34 rad/s.
Explanation:
Considering the following parameters,
Length = 3.40 m
Distance = 5.90 m
Angle = 45.0°
We are tasked with finding the angular speed of rotation
Using the balance equation
Horizontal component
Vertical component
Substituting the tension value
Substituting the value into the equation
Thus, the angular speed of rotation computes to 1.34 rad/s.