Answer:
The specific gravity of the saturated solution is 2
Explanation:
Specific gravity represents the ratio of the density of a solution, in this case, a saturated potassium iodide (KI) solution, to the density of water. Assuming the density of water is 1:
Specific gravity = Density
Density itself is defined as the mass divided by volume.
In 100mL of water, the mass of dissolve-able KI is:
100mL * (1g KI / 0.7mL) = 143g of KI
This indicates that all 100g of KI dissolves (Mass solute)
With 100mL of water corresponding to a mass of 100g (Mass solvent)
The overall mass of the solution computes to 100g + 100g = 200g
In a volume of 100mL, the solution's density is:
200g / 100mL = 2g/mL.
Specific gravity is a dimensionless quantity, thus the specific gravity of the saturated solution is 2
Answer:
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Explanation:
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Response:B) The octet of the carbon atom is incomplete within the molecule.
Explanation:
The result is: 6.022·10²² molecules of glucose.
c(glucose) = 100 mM.
c(glucose) = 100 · 10⁻³ mol/L.
c(glucose) = 0.1 mol/L; concentration of the glucose solution.
V(glucose) = 1 L; volume of the glucose solution.
n(glucose) = c(glucose) · V(glucose).
n(glucose) = 0.1 mol/L · 1 L.
n(glucose) = 0.1 mol; quantity of substance.
N(glucose) = n(glucose) · Na (Avogadro's number).
N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.
N(glucose) = 6.022·10²².
For an alcohol to be oxidized, it cannot be a tertiary alcohol.
A tertiary alcohol features the -OH group bonded to a carbon that is also connected to three other carbon atoms. This configuration prevents the alcohol group from engaging in oxidation, which is why tertiary alcohols do not oxidize under mild conditions.
