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svetoff
1 month ago
3

You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. unfo

rtunately, you have the density of mercury in units of kilogrammeter3 and the density of silicon in other units: 2.33 gramcentimeter3. you decide to convert the density of silicon into units of kilogrammeter3 to perform the comparison. by which combination of conversion factors will you multiply 2.33 gramcentimeter3 to perform the unit conversion?

Physics
2 answers:
inna [3.1K]1 month ago
3 0

Here's my answer; is it correct?

Maru [3.3K]1 month ago
3 0

The correct answer is to multiply by 1000.

Since 1 g/cm³ equals 1000 kg/m³, converting 2.33 g/cm³ to kg/m³ requires multiplying by 1000.

Calculation: 2.33 × 1000 = 2330

Therefore, 2.33 g/cm³ is equivalent to 2330 kg/m³.


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An ideally efficient heat pump delivers 1000 J of heat to room air at 300 K. If it extracted heat from 260 K outdoor air, how mu
Yuliya22 [3333]

Answer:

Wnet, in, = 133.33J

Explanation:

Provided that

Pump heat QH = 1000J

Hot temperature TH= 300K

Cold temperature TL= 260K

Given the heat pump is entirely reversible, the performance coefficient expression is formulated as follows:

According to the first law of thermodynamics,

COP(HP, rev) = 1/(1-TL/TH)

COP(HP, rev) = 1/(1-260/300)

COP(HP, rev) = 1/(1-0.867)

COP(HP, rev) = 1/0.133

COP(HP, rev) = 7.5

The power necessary to operate the heat pump is given by

Wnet, in = QH/COP(HP, rev)

Wnet, in = 1000/7.5

Wnet, in = 133.333J. QED

Thus, the 133.33J represents the initial work input during the heat transfer process.

<padditionally...><pbased on="" the="" first="" law="" rate="" at="" which="" heat="" is="" extracted="" from="" lower="" temperature="" reservoir="" calculated="" as="">

QL=QH-Wnet, in

QL=1000-133.333

QL=866.67J

</pbased></padditionally...>
5 0
1 month ago
Four particles with masses 2 kg, 5 kg, 2 kg, and 2 kg are connected by rigid rods of negligible mass as shown. assume the system
Maru [3345]
The answer is 10pi. I believe this will be helpful.
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15 days ago
Evaluate the final kinetic energy of the supply spacecraft for the actual tractor beam force, F(x)=αx3+βF(x)=αx3+β.
Sav [3153]

Answer:

K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x

Explanation:

To calculate the kinetic energy variation, we can utilize the work-energy theorem.

W = ΔK

∫ F .dx = K - K₀

If the object starts from rest, then K₀ = 0.

So, ∫ F dx cos θ = K.

As the force and displacement directions align, the angle is zero, and hence the cosine is 1.

Now we can substitute and perform integration:

α ∫ x³ dx + β ∫ dx = K.

Thus, α x⁴ / 4 + β x = K.

Next, we evaluate from the limits F = 0 to F:

α (x⁴ / 4 - 0) + β (x - 0) = K.

Consequently, K = αX⁴ / 4 + β x.

This results in K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x.

To finalize the computation, we need to ascertain the displacement.

8 0
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the answer is 2w
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