answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Troyanec
1 day ago
9

a water heater has a power rating of 1 kW. how many seconds will this heater take to boil 1 liter of water?

Physics
You might be interested in
You, Archimedes, suspect that the king’s crown is not solid gold but is instead gold-plated lead. To test your theory, you weigh
inna [3103]

Answer:

a) 16675.75 Kg/m³ b) 77.6%

Explanation:

The weight of the crown is 60 N, with gold's density at 19300 Kg/m³, lead's at 11340 kg/m³, water's at 1000kg/m³, and gravitational acceleration at 9.8 m/s².

The upthrust acting on the crown equals the weight in air minus its weight in water: 60 - 56.4 results in 3.6 N.

This leads to the mass of water displaced being 3.6 / 9.8, as weight equals mass times gravity.

The mass of displaced water is 0.367 Kg.

The density of water relates mass to volume as: 1000 = 0.367 / volume.

Cross-multiplying helps us determine the volume:

The crown’s volume becomes 0.367 / 1000 = 0.000367 m³ since it displaces an equal volume of water per Archimedes' principle.

Let V1 denote the gold volume and V2 the lead volume.

Total volume for the crown becomes V1 + V2.

Likewise, using the relationship of densities:

Density of gold translates to mass of gold over V1 and lead density translates to mass of lead over V2.

Thus, 19300 = mass of gold in the crown / V1 and 11340 = mass of lead in the crown / V2.

Combining them gives us: 19300 V1 = mass of gold and 11340 V2 = mass of lead.

Adding together leads to: 19300 V1 + 11340 V2 = weight of the crown / 9.8.

So, 19300 V1 + 11340 V2 = 6.12.

From V1 + V2 = 0.000367, we can express V1 in relation to V2.

V1 = 0.000367 - V2.

Substituting this into the mass equation results in:

19300 (0.000367 - V2) + 11340 V2 = 6.12.

Expanding gives:

7.083 - 19300 V2 + 11340 V2 = 6.12.

Reorganizing yields:

-7960 V2 = 6.12 - 7.083.

So, -7960 V2 = -0.963.

This leads to V2 = -0.963 / -7960 = 0.000121 (the lead volume in the crown).

Substituting V2 back into the total volume equation gives:

V1 + 0.000121 = 0.000367 m³

Thus, V1 = 0.000367 - 0.000121 = 0.000246 m³ (the gold volume in the crown).

Which leads to the mass of gold in the crown = 19300 × 0.000246 = 4.748 kg.

The mass of lead equals 11340 × 0.000121 = 1.372 kg.

The average density for the crown calculates as (mass of gold + mass of lead) / total volume = 6.12 / 0.000367 = 16675.75 kg/m³.

b) The percentage of gold by weight computes to mass of gold / total mass × 100 = approximately 77.6%.

4 0
3 months ago
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u
Yuliya22 [3333]

Answer:

The total energy can be expressed as T = 169.02 \ J

Explanation:

The problem states that

The Poynting vector, which measures energy flux, equals k = 0.939 \ W/m^2

The rectangle's length is represented by l = 1.5 \ m

The width of the rectangle is w = 2.0 \ m

The duration considered is t = 1 \ minute = 60 \ s

Mathematically, the overall electromagnetic energy incident on the area is given by

T = k * A * t

where A denotes the area of the rectangle, calculated as

A= l * w

By plugging in the respective values

A= 2 * 1.5

A= 3 \ m^2

Again substituting values

T = 0.939 * 3 * 60

T = 169.02 \ J

5 0
3 months ago
A positive point charge q is placed at the center of an uncharged metal sphere insulated from the ground. The outside of the sph
Softa [3030]
B. The charge on A is -q; B has no charge. Given that a positive charge is situated at the center of an uncharged metallic sphere which is insulated and disconnected from the ground, a negative charge (-q) will appear on the inner surface A of the sphere. Should the exterior surface B be grounded, it will become neutral, resulting in no charge remaining on surface B.
4 0
2 months ago
The fastest animal in the world is the peregrine falcon. It is capable of diving after its prey at an amazing 83.00 meters per s
Maru [3345]
1 meter per second converts to 2.237 miles per hour

therefore, 83 m/sec is equal to 185.666 miles per hour!!...here is the answer!!

6 0
3 months ago
Read 2 more answers
A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equa
Keith_Richards [3271]

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

Given data:

Person's weight = 625 N

Bike's weight = 98 N

Pressure per tire = 7.60 x 10⁵ Pa

Find: Contact area per tire

Total system weight = 625 + 98 = 723 N

Let F represent the force supported by each tire

2F = 723 N

Therefore, F = 361.5 N

Using the formula F = P × A

A = \dfrac{F}{P}

A = \dfrac{361.5}{7.60 \times 10^5}

Contact area, A = 4.76 x 10⁻⁴ m²

7 0
3 months ago
Other questions:
  • Bonnie and clyde are sliding a 300 kg bank safe across the floor to their getaway car. the safe slides with a constant speed if
    14·1 answer
  • A 7.0-kilogram cart, A, and a 3.0-kilogram cart, B, are initially held together at rest on a horizontal, frictionless surface. W
    7·1 answer
  • A kinesin that is transporting a secretory vesicle uses approximately 80 ATP molecules/s. Each ATP provides a kinesin molecule w
    7·1 answer
  • Use the momentum equation for photons found in this week's notes, the wavelength you found in #3, and Plank’s constant (6.63E-34
    14·2 answers
  • A 1200-ft equal-tangent crest vertical curve is currently designed for 50 mi/h. A civil engineering student contends that 60 mi/
    11·1 answer
  • A turtle takes 3.5 minutes to walk 18 m toward the south along a deserted highway. A truck driver stops and picks up the turtle.
    11·1 answer
  • The electric potential in a region that is within 2.00 mm of the origin of a rectangular coordinate system is given by V=Axl+Bym
    5·1 answer
  • 2.27 A gas is compressed from V1= 0.3 m3, p1=1 bar to V2= 0.1 m3, p2 =3 bar. The pressure and
    15·1 answer
  • A wheel accelerates uniformly from rest to an angular speed of 25 rad/s in 10 s.(a) Find the angular acceleration of the wheel.
    15·1 answer
  • A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!