1. A spur gear made of bronze drives a mid steel pinion with angular velocity ratio of 13 /2 : 1. Thepressure angle is 14 1/2° .

Answer:

A fluid is a material that maintains continuous and permanent deformity when a shearing stress is applied.

• The pressure at a given point in a fluid remains unaffected by the direction of the surface that intersects this point; this pressure is isotropic.

• The force generated by pressure p acting on one side of a minimal surface area dA defined by a unit normal vector n can be expressed as −pndA.

• The speed at which pressure is conveyed through a fluid matches the speed of sound.

• The units employed vary based on the selected system, incorporating measures such as feet, seconds, newtons, and pascals. On the other hand, a dimension refers to a more abstract idea, encompassing terms like mass, length, and time.

• The specific gravity (SG) of a solid or liquid is the proportion of its density compared to that of water at the identical temperature.

• A Newtonian fluid is characterized by the viscous stress being directly proportional to the strain rate (velocity gradient). The viscosity, µ, is a property of the fluid that varies with temperature.

• At the boundary between solid and fluid, the velocities of both the fluid and solid coincide; this situation is referred to as the “no-slip condition.” Consequently, with high Reynolds numbers (>> 1), boundary layers develop near the solid surface. In those layers, significant velocity gradients occur, resulting in crucial viscous influences.

• At the junction of two distinct fluids, surface tension may play a significant role. Surface tension leads to the emergence of phenomena like meniscus, drops, bubbles, and capillary rise seen in narrow tubes since it can counterbalance pressure variations across the interface.

Answer:

The resolution for this question is below in the explanation section.

Explanation:

The right response to this question is A, which is 112002.

The correct code relating to this question is presented below

#include  <stdio.h>

#include  <string.h>

#include  <sys/types.h>

//#include "csapp.h"

void end(void)

{

printf("2");

}

int main()

{

if (fork() == 0)

atexit(end);

if (fork() == 0)

else

exit(0);

}

/* $end forkprob2 */

When this program is executed, the fork function will yield varying results.

However, it should be noted that running it multiple times will produce inconsistent values. The most common output the program will generate is A.

Attached is an image of the program's execution for further clarification.

Answer:Ensure the correct cable is connected between the laptop and the projector. Check for HDMI inputs or 15-pin video output interfaces.

Also, make sure the laptop is set to project to the correct display output.

Explanation:

Answer:

The velocity at exit U_2 is 578.359 m/s

The exit diameter d_e is 1.4924 cm

Explanation:

Provided data includes:

Length of the nozzle L = 25 cm

Inlet diameter d_i = 5 cm

At the nozzle entrance (state 1): Temperature T_1 = 325 °C, Pressure P_1 = 700 kPa, Velocity U_1 = 30 m/s, Enthalpy H_1 = 3112.5 kJ/kg, Volume V_1 = 388.61 cm³/gAt the nozzle exit (state 2): Temperature T_2 = 250 °C, Pressure P_2 = 350 kPa, Velocity U_2, Enthalpy H_2 = 2945.7 kJ/kg, Volume V_2 = 667.75 cm³/g To determine:a. Exit Velocity U_2b. Exit Diameter d_e

a.The Energy Equation can be represented by:ΔH + ΔU² / 2 + gΔz = Q + WAssuming Q = W = Δz = 0Substituting the values yields:

(H_2 - H_1) + (U²_2 - U²_1)  / 2 = 0From which we can derive U_2 = sqrt((2* (H_1 - H_2 )) + U²_1) with the calculations leading to U_2 = sqrt ( 2 * 10^3 * (3112.5 -2945.7) + 900) yielding U_2 = 578.359 m/s

b.

Using mass balance approach, we have U_1 * A_1 / V_1 = U_2 * A_2 / V_2

This leads to U_1 * d_i² / V_1 = U_2 * d_e² / V_2, thus d_e = d_i * sqrt((U_1 / U_2) * (V_2 / V_1)). Hence, d_e = 5 * sqrt((30 / 578.359) * (667.75 / 388.61)) computes to d_e = 1.4924 cm