A 5.00-kg box is suspended from the end of a light vertical rope. A time dependent force is applied to the upper end of the rope

Answer: total angular distance = 1700° and 29.7 rad

   the total angular displacement = 0

Explanation:

This is a breakdown of the calculations needed.

The task is to determine both the total angular distance and displacement experienced by the knee.

To calculate the distance traveled by the knee, consider that when squatting, the knee bends 85° to lower, and then another 85° to return to standing (upright). Thus, the cumulative angular movement during the squat totals 170°.

For 10 squats, the knee must undergo 170° motion multiplied by 10, resulting in:

10 * 170° = 1700°

As such, the total angular distance reached is 1700°.

Now converting this to radians since both degree and radian outputs are required:

Since 2π equals 360°, it follows that one degree equates to about 57.3°;

∅ (rad) = ∅ (deg) * 2π/360°

∅ (rad) = 1700° * 2π/360° = 29.7 rad

∅ (rad) = 29.7 rad

For the second part, remember that angular displacement is determined by the angular distance divided by time, leading to a displacement of zero because the knee's ending position is the same as its starting position.

I hope this is helpful!!!!

π

True. Explanation: In this instance, the area of the graph represents the impulse. Impulse is defined as the change in an object's momentum. Moreover, it is also expressed as the product of the force acting on an object and the duration of the impact. When we graph the force against time, if the force remains constant, the resultant graph will take on a rectangular shape, and the area under that graph will equal the impulse's definition.

Answer:

 a

    The density of volume charge is  

b

    The density of surface charge is  

Explanation:

The question states that

    The radius measures  R

     The length is L

       The speed is  v

        The ion count per unit volume is  n

         The charge per ion is  q

          The surface thickness of the cylinder is  

The volume charge density is mathematically expressed as

     

The surface charge density is mathematically expressed as

   

substituting for  

     

     

At time , the ball's horizontal and vertical velocities can be represented as

However, since the ball is thrown horizontally, we have . The horizontal and vertical positions at time are

The ball travels a distance of 22 m horizontally from the throw point, thus

With this, we determine that the time for the ball to reach the ground is

When it touches down, and