1) The electric potential energy can be defined as the product of the electric potential and the associated charge:
where
q refers to the charge
V denotes the electric potential
In this scenario, the charge on the rod is
, and the potential energy is
, thus we may rearrange the earlier formula to find the electric potential at the tip:
2) Using this same formula, if the charge changes to
, the resulting electric potential will be:
Answer:
Insufficient details provided; please clarify further.
a) Average power: 1425 W
b) Instantaneous power at 3.0 seconds: 2850 W
Given that the object moves along the ramp with uniform acceleration due to a constant force, we can apply the suvat equation:
s = 18 m (the distance covered along the ramp)
u = 0 (initial speed)
t = 3.0 s (time taken)
a is the acceleration of the object along the ramp
Calculating the acceleration 'a' using this data,
Next, we use Newton's second law to determine the net force acting on the object:
This net force consists of the applied force acting forward and the backward component of weight, allowing us to calculate the applied force.
m = 24 kg (mass of the object)
Now, we can compute the work done by the applied force, which runs parallel to the ramp:
s = 18 m (displacement)
The average power required is thus determined.
b) The instantaneous power at any point during the motion can be calculated using:
where F is the force applied and v is the object's velocity.
With the previously calculated applied force, as this is uniformly accelerated motion, we can also find the velocity at the end of the 3.0 seconds using the suvat equation:
