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OlgaM077
4 hours ago
14

Is the atom indicated with an arrow nucleophilic, electrophilic, acidic, more than one of these choices, or none of these choice

s? (For purposes of this question, acidic is defined as pKa ≤ 25.)

Chemistry
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You are standing on the rim of a canyon, you drop a rock and in 7.0 seconds hear the sound pof it hitting the bottom, how deep i
VMariaS [2998]
This should assist you with your inquiry: Gravitational acceleration = 9.8 m/s². The formula is 1/2 x 9.8 x 7² = 240.1 m, indicating that the rock has fallen a distance of 240.1 m. I can't assist with additional details, but this should provide a foundation.
8 0
2 months ago
Section 1.7 showed that in 1997 los angeles county air had carbon monoxide (co) levels of 15.0 ppm. an average human inhales abo
castortr0y [3046]

Given data:

CO concentration in air = 15 ppm

Volume of air inhaled per breath = 0.50 L

Breaths taken per minute = 20

CO density = 1.2 g/L

Objective:

milligrams of CO inhaled over 6 hours

Clarification:

A concentration of 15 ppm of CO means that there are 15 liters of CO per 10⁶ liters of air

. Consequently, the volume of CO inhaled through 0.50 L of air is

= 15 L CO * 0.50 L air/10⁶ L air = 7.5 *10⁻⁶ L CO/breath

Next, considering there are 20 breaths in a minute,

the total number of breaths in 360 minutes (or 6 hours) will be

= 360 min * 20 breaths/1 min = 7200 breaths

Thus, the total volume of CO inhaled in that time frame is

= 7200 breaths * 7.50*10⁻⁶L/1 breath = 0.054 L

Given that the density of CO is 1.2 g/L

the mass of CO inhaled equals Density*Volume

= 0.054 * 1.2 = 0.0648 g = 64.8 mg

Thus, the mass of CO inhaled over 6 hours is 64.8 mg


7 0
2 months ago
Read 2 more answers
Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up
lions [2927]

Answer:

A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

According to the Second Law of Thermodynamics, not all energy produced when tires are incinerated can be effectively used due to losses associated with finite temperature differences. The energy obtainable from a tire when burned, measured in kilowatt-hours (E_{out}), can be calculated using the efficiency definition:

E_{out} = \eta \cdot E_{in}

Where:

\eta - Efficiency, which is dimensionless.

E_{in} - Energy released from burning, measured in kilowatt-hours.

Taking into account \eta = 0.5 and E_{in} = 75\,kWh, the yearly energy yield from a tire amounts to:

E_{out} = 0.5\cdot (75\,kWh)

E_{out} = 37.5\,kWh

Thus, the number of tires necessary to meet the electricity demand of ten homes for one year is:

n = \frac{(10\,homes)\cdot \left(10000\,\frac{kWh}{home} \right)}{37.5\,\frac{kWh}{tire} }

n = 2666.667\,tires

A total of 2667 tires are necessary to satisfy the annual power needs of ten homes.

8 0
2 months ago
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