To find the number of particles, use the formula: 2.0 g multiplied by (6.0 x 10^23 particles per mol) divided by 20.18 g/mol. Thus, Option C is accurate.
Answer:
0.133
Explanation:
The reaction that occurs between KIO3 and KI in an acidic medium is described as
IO3⁻ +5I⁻ +6h⁺ → 3I₂ + 3H₂O
I₂ subsequently reacts with sodium thiosulfate
NaS₂O₃ → 2Na⁺ + S₂O₃²⁻
The overall reaction can be summarized as
IO⁻₃ + 6H⁺ + 6S₂O₃³⁻ → I⁻ + 3S₄O₆²⁻ + 3H₂O
The mole of KIO₃
is computed using molarity multiplied by volume

which equals 0.00002mol
One mole of KIO₃ reacts with 6 moles of S₂O₃²⁻
which gives 2x6x10⁻⁵
= 0.00012 mol
The volume is 0.90 ml
1 ml equals 0.001L
0.90ML is 0.0009L
To find concentration,
molarity/volume
= 0.00012/0.0009
= 0.133m