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nataly862011
19 days ago
6

A 0.1014 g sample of a purified compound containing C, H, and, O was burned in a combustion apparatus and produced 0.1486 g CO2

and 0.0609 g of H2O. What is the empirical formula of this compound?
Chemistry
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Which statement is true about writing chemical formulas of covalent compounds?
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How many iodide ions are present in 65.5ml of .210 m AlI3 solution
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Answer:

2.48\times 10^{22} ions are present in solution.

Explanation:

Molarity of the solution = 0.210 M

Volume of the solution = 65.5 ml = 0.0655 L

Moles of aluminum iodide = n

Molarity=\frac{\text{Moles of compound}}{\text{Volume of the solution(L)}}

0.210M=\frac{n}{0.0655 L}

n = 0.013755 moles of aluminum iodide

Each mole of aluminum iodide yields 3 moles of iodide ions:

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The total number of iodide ions in 0.041265 moles:

0.041265 mol\times 6.022\times 10^{23}=2.48\times 10^{22} ions

2.48\times 10^{22} ions are present in solution.

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A 1.555-g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. Refer to Example Exercise 14.l and show the calc
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