Answer:
Explanation:
Provided:
mass of the steel ball 
initial velocity of the ball 
Final velocity of the ball 
(moving upwards)
The impulse given is determined by the change in the momentum of the object.
<ptherefore the="" impulse="" j="" is="" defined="" by="">
Thus, the magnitude of the Impulse is 4 N-s.
</ptherefore>
Answer:
0.018 J
Explanation:
The work required to bring the charge from infinity to the point P is equal to the change in its electric potential energy. This can be expressed as
where
represents the charge's magnitude
and 
signifies the potential difference between point P and infinity.
After substituting into the formula, we arrive at
Answer:
A rock weighing 50kg should be positioned at a distance of 0.5m from the pivot of the seesaw.
Explanation:
τchild=τrock
We will utilize the formula for torque:
(F)child(d)child)=(F)rock(d)rock)
The gravitational force acts equally on both objects.
(m)childg(d)child)=(m)rockg(d)rock)
We can eliminate gravity from both sides of the equation for simplification.
(m)child(d)child)=(m)rock(d)rock)
Now employing the given masses for the rock and child. The seesaw's total length is 2 meters, with the child sitting at one end, placing them 1 meter from the center of the seesaw.
(25kg)(1m)=(50kg)drock
Solve for the distance where the rock should be positioned in relation to the seesaw's center.
drock=25kg⋅m50kg
drock=0.5m
Answer:
The car that is the furthest from the finish line is: Car III (Choice C).
Explanation:
Here, we seek the car with the lowest overall average speed throughout the race. Thus, the one in last place inherently possesses the slowest average speed.
Since Car III is significantly behind Cars I and II, Choice A and B cannot be correct. Choice D is also not valid, as the positions of the cars are not the same. Lastly, Choice E is incorrect due to sufficient evidence demonstrating that Choice C has the lowest average speed.
