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1 month ago

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Several charges in the neighborhood of point P produce an electric potential of 6.0 kV (relative to zero at infinity) and an ele

ctric field of N/C at point P. Determine the work required of an external agent to move a 3.0-μC charge along the x axis from infinity to point P without any net change in the kinetic energy of the particle.

1 answer:

ValentinkaMS [3.4K]1 month ago

4 0

Answer:

0.018 J

Explanation:

The work required to bring the charge from infinity to the point P is equal to the change in its electric potential energy. This can be expressed as

$W = q \Delta V$

where

$q=3.0 \mu C = 3.0 \cdot 10^{-6} C$ represents the charge's magnitude

and $\Delta V = 6.0 kV = 6000 V$ signifies the potential difference between point P and infinity.

After substituting into the formula, we arrive at

$W=(3.0\cdot 10^{-6}C)(6000 V)=0.018 J$

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