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mixer
9 days ago
13

Will two separate 50db sounds together constitute a 100db sound explain mathematical

Physics
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A football game begins by flipping a penny to decide which team will get the ball first. The 5.25 g penny has a speed of 3.27 m/
ValentinkaMS [3465]
To start, we first need to determine the kinetic energy of the penny before it strikes the ground. This is calculated using the formula where m equals 5.25 g, which is 0.00525 kg for the penny's mass, and v equals 3.27 m/s for its speed. Replacing the values into the equation provides: When the penny lands, all this kinetic energy transforms into internal energy for both the penny and the ground. If half of this energy goes into the penny's internal energy, the change is determined by a specific formula where m is the penny's mass, Cs is its specific heat capacity (2.03 J/gC), and \Delta T, the change in temperature. To find the last element, the equation will be solved.
3 0
2 months ago
How many top quark lifetimes have there been in the history of the universe (i.e., what is the age of the universe divided by th
inna [3103]

Answer:

times1.0\cdot 10^{41}

Explanation:

To approach this question, we first express the universe's age and the top quark's lifespan in scientific notation.

Age of the universe:

T=100,000,000,000,000,000s = 1.0\cdot 10^{17} s (1 followed by 17 zeros)

Lifetime of the top quark:

\tau = 0.000000000000000000000001s = 1.0\cdot 10^{-24} s (the decimal point is shifted 24 places to the right)

To provide an answer, we will compute the ratio of the age of the universe to the lifespan of the top quark:

r = \frac{T}{\tau}=\frac{1.0\cdot 10^{17} s}{1.0\cdot 10^{-24} s}=1.0\cdot 10^{41}

6 0
3 months ago
[High Dive) above a pool of water. According to the announcer, the divers enter the water at a speed of 56 mi/h (25 m/s). (Air r
Yuliya22 [3333]

Answer:

(a) The announcer's statement is inaccurate since the divers enter the water with a speed of 20.4, not 25 m/s as claimed

(b)  a diver could enter the water at a speed of 25 m/s if their initial velocity was 14.4 m/s. However, achieving this upward initial speed is not physically feasible

Explanation:

(a)

To determine the final velocity V_{f} for an object moving a distance h with an initial vertical velocity V_{i} the kinematic equation takes the form

V_{f}^{2}=V_{i}^{2}+2ah where a is acceleration

Using g for a, where g is taken as 9.81

V_{f}^{2}=V_{i}^{2}+2gh

With an initial speed of zero, we find the final velocity using substitutions, noting that 70 ft converts to 21.3 m for h

V_{f}=\sqrt {(2gh)}= V_{f}=\sqrt {(2*9.81*21.3)}= 20.44275

Thus, divers descend at a rate of 20.4 m/s

The announcer's statement is incorrect as divers enter at 20.4 and not at 25 m/s as stated

(b)

Divers can achieve a velocity of 25 m/s if they possess an initial velocity. Utilizing the kinematic equation

V_{f}^{2}=V_{i}^{2}+2gh

With a final speed of 25 m/s

V_{i}^{2}=2gh-V_{f}^{2}

V_{i}=\sqrt{(V_{f}^{2}-2gh)}

V_{i}=\sqrt{(25^{2}-2*9.81*21.3)}= 14.390761 m/s

This indicates that it is conceivable for a diver to enter the water at 25 m/s assuming an initial velocity of 14.4 m/s

Ultimately, the required initial velocity is not achievable physically

3 0
2 months ago
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