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zhenek
15 days ago
14

The compound Xe(CF3)2 decomposes in a first-order reaction to elemental Xe with a half-life of 30.0 min. If you place 4.5 mg of

Xe(CF3)2 in a flask, calculate how long you must wait until only 0.25 mg of Xe(CF3)2 remains?
Chemistry
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Reaction of (r)-2-chloro-4-methylhexane with excess nai in acetone gives racemic 2-iodo-4-methylhexane. what is the explanation
alisha [2963]

I believe this question has five choices available:

 

>an SN2 process has happened with reversal of configuration

>racemization followed by an S N 2 reaction

>an SN1 process has occurred resulting in reversal of configuration

>an SN1 reaction has taken place due to the formation of a carbocation

>an SN1 event followed by an S N 2 “backside” attack

 

 

 

The correct choice is:

an SN1 reaction has occurred due to carbocation formation 

4 0
2 months ago
C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Tems11 [2777]

Response:

Ethanol serves as a reducing agent.(C_2H_5OH)

The lowest integer coefficient for MnO_4^- in the balanced equation is 4

Clarification:

A redox reaction, or oxidation-reduction reaction, is defined as one in which oxidation and reduction processes occur simultaneously.

Oxidation is the process whereby a substance loses electrons, resulting in an increase in oxidation state. In contrast, reduction entails a substance gaining electrons, leading to a decrease in oxidation state.

Reducing agents enable other substances to undergo reduction while becoming oxidized themselves.

Conversely, oxidizing agents facilitate other substances' oxidation while being reduced in the process.

For the chemical reaction in question, the half-reaction would be:

Oxidation:

Reduction:

To balance the oxygen atoms on both sides

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

For oxidation:

For reduction:

C_2H_6O\rightarrow C_2H_4O_2

MnO_4^-\rightarrow Mn^{2+}Then balance the hydrogen atoms on both sides.

  • For oxidation:
For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2

Lastly, balance the charge.MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • For oxidation: For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

To balance the electrons, multiply the oxidation reaction by 5 and the reduction by 4 before combining both equations for a balanced redox reaction.

MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2OOxidation:

  • Reduction:
The finalized balanced chemical equation in acidic conditions will be:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In this redox process, ethanol acts as the reducing agent while the permanganate ion serves as the oxidizing agent.

4 0
2 months ago
How many atoms of ^6Li are there in 12.3 g of ^6Li?
alisha [2963]

Answer:6.94

Explanation:Atomic mass of Li = 6.94

To find the number of atoms: 12.6 g Li x 1 mole/6.94 g x 6.02x10^23 atom/mole = 1.09x10^24 atoms

8 0
4 months ago
How many moles of n2(g) would contain exactly 4.0 moles of nitrogen atoms?
VMariaS [2998]

Each nitrogen molecule consists of 2 nitrogen atoms.
Thus, 2 moles of nitrogen gas molecules result in 4 moles of nitrogen atoms. The answer is 2 moles.

4 0
4 months ago
Read 2 more answers
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