As a 5.0 x 10^2 newton basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on th

Answer:

Explanation:

When calculating Hall voltage, it is crucial to have the current, magnetic field strength, length, area, and number of charge carriers available. The Hall voltage can be expressed using the equation:

Where:

i= the current

B= the magnetic field strength

L = the length

n = the number of charge carriers

e= charge of an electron

We need to replace values and solve for n:

As a result, the charge carrier density is

The amount of work performed by a system at consistent pressure is defined by the following equation:

where
p represents pressure
as the final volume
as the initial volume

Plugging the values given in this case into the formula gives us


Considering that , the result for the work done becomes

Answer:

a

The value at a point inside is Zero

b

The electric field is

Explanation:

We know from the problem that

The charge magnitude is

The radius of the spherical ball is

According to Gauss’s law, the enclosed charge within a conductor is zero which indicates that the electric field within the spherical ball is zero

On the outside, the electric field around the spherical ball is mathematically expressed as

Here a denotes a point outside the spherical ball with its value of

and k represents Coulomb's constant, valued at

=>

=>

Hypothesis: An increase in voltage should result in a corresponding rise in current because according to Ohm's Law,

Ohm's Law indicates that current is proportional to voltage when resistance remains constant. Hence, if resistance stays the same, elevating the voltage will lead to an increase in current. Conversely, if voltage remains unchanged and resistance increases, current will decrease.