Result:
, 
Explanation:
The electromagnetic attraction between the electron and the proton in the nucleus is equivalent to the centripetal force:
where
k represents the Coulomb constant
e denotes the charge of the electron
e denotes the charge of the proton in the nucleus
r signifies the distance from the electron to the nucleus
v indicates the velocity of the electron
is the mass of the electron
Rearranging for v, we determine
Inside a hydrogen atom, the distance separating the electron from the nucleus is roughly
while the mass of the electron is
and the charge is
By plugging in the values into the formula, we achieve
<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.
For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26
For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
Solution:
/ Em₀ = 0.30
Explanation:
In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.
K = ½ m v²
U = mgh
We assess the mechanical energy at two positions:
Initial. Lower
Em₀ = K = ½ m v²
At its highest point
= U = mg and
Now let's compute
Em₀ = ½ m 3.6²
Em₀ = m 6.48
= m 9.8 × 0.2
= m 1.96
Thus the energy lost is given by:
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
This means that 30% of the sun's energy is transformed into potential energy.
There are various conversion possibilities.
This energy changes into thermal energy affecting the spores and air, since it cannot be regained.
