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Shtirlitz
8 days ago
11

A vehicle ___________ occurs when the driver begins to back up and is unaware that a person is behind the vehicle.

Physics
2 answers:
kicyunya [1K]8 days ago
8 0

Answer:

The answer is back over.

Maru [1K]8 days ago
6 0
I'm unaware of the term accident?
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Uzupełnij zdania właściwymi sformułowaniami. Wyobraź sobie, że między linę a siodełko karuzeli łańcuchowej wmontowany jest siłom
ValentinkaMS [1144]

Explanation:

Here’s a revised version of the requirements;

Fill in the blanks with the appropriate terms. Picture a force gauge fixed between the rope and the saddle of the chain carousel. If you keep your feet off the ground while the vehicle is not in motion, the dynamometer shows A / B. When the carousel is spinning, you’ll see C / D displayed on the dynamometer.

A. Your weight including the saddle

C. Value of the rope's strength

B. Your weight

D. Value of the centripetal force

3 0
15 days ago
Compare the time period of two simple pendulums of length 4m and 16m at a place.
Ostrovityanka [942]

Answer:

The period of the pendulum measuring 16 m is double that of the 4 m pendulum.

Explanation:

Recall that the period (T) of a pendulum with length (L) is defined by:

T=2\,\pi\,\sqrt{ \frac{L}{g} }

where "g" denotes the local gravitational acceleration.

Since both pendulums are positioned at the same location, the value of "g" will be consistent for both, and when we compare the periods, we find:

T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2

Thus, the duration of the 16 m pendulum is two times that of the 4 m one.

5 0
3 days ago
Can pockets of vacuum persist in an ideal gas? Assume that a room is filled with air at 20∘C and that somehow a small spherical
kicyunya [1011]

Answer:

The time required is 20 μs

Explanation:

Here is the data provided:

temperature = 20°C  = 293 K

radius = 1 cm

atomic mass of air = 29 u

To determine

the duration for air to refill the vacuum space

solution:

We calculate the root mean square velocity of air particles. This can be expressed as:

\frac{1}{2}mv^2 = \frac{3}{2}RT

where m indicates mass, t is temperature, v is speed, and R is the ideal gas constant, which is approximately 8.3145 (kg·m²/s²)/K·mol.

v = \sqrt{\frac{3RT}{M} }............................1

v = \sqrt{\frac{3(8.314)293}{29*10{-3}kg} }

Resulting in v = 501.99 m/s.

<pNow, to cover the distance of 1 cm,<pThe duration needed for air is calculated as:

time taken = \frac{r}{v}

which gives us:

time taken = \frac{1*10^{-2}m}{501.99}

so, time taken = 19.92 × 10^{6} seconds = 20μs.

Thus, the required time is 20 μs.

3 0
10 days ago
The solar panels used by Mark function because of the photoelectric effect. Light shines on the cells causing electrons to be ej
Ostrovityanka [942]

 Could a friend confirm this answer? I'm not completely certain, but I believe that visible light is required to generate the photoelectric effect.

4 0
1 day ago
Read 2 more answers
un serbatoio d'acqua di forma cilindrica è riempito con acqua dolce fino a un livello di 6,40 m calcola la pressione dell'acqua
Maru [1053]
Per determinare la pressione a una certa profondità, si applica la legge di Stevino:
<span>p = ρ · g · h

Con g = 9,81 m/s² e ρ = 1000 kg/m³

Calcoliamo:
p(h₁) = 1000 · 9,81 · 4,50 = 44145 Pa
p(h₂) = 1000 · 9,81 · 5,50 = 53955 Pa

</span>
6 0
17 days ago
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