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Svetlanka
4 days ago
10

The combustion of propane is represented by the following chemical equation. C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(l) The standard enthalp

ies of formation ( ΔH∘f ) for C3H8(g), CO2(g), and H2O(l) are −103.8 kJ/mol, −393.5 kJ/mol, and −285.8 kJ/mol respectively. What is the enthalpy of combustion for propane at 25 °C and 1 atm?
Chemistry
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From the following list of elements, those that will always form ionic compounds in a 1:2 ratio with zinc.
eduard [2782]
A. iodine C. fluorine F. bromine Explanation: Ionic bonds primarily form between metals and non-metals, typically where there exists a significant difference in electronegativity between the constituent atoms. This situation results in one atom seeking to gain electrons while the other donates them. For zinc to form a compound in a 1:2 ratio, its combining power must align accordingly. The prevalent oxidation state of zinc is +2. The other combining atoms must also possess the capacity to accept two electrons. The halogens fit perfectly here, as they require only one electron to achieve stability and are highly electronegative. Hence, if two halogens combine with zinc, they will result in an ionic bond. The relevant halogens include fluorine, chlorine, bromine, iodine, and astatine which will yield compounds: ZnF₂, ZnBr₂, and ZnI₂.
3 0
3 months ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
KiRa [2933]

Response: k = 23045 N/m

Clarification:

To determine the spring constant, one must consider the maximum elastic potential energy that the spring can withstand. The kinetic energy of the vehicle should equal at minimum the elastic potential energy of the spring when it is fully compressed. Hence, we express it as:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the vehicle = 1050 kg

k: spring constant =?

v: car speed = 8 km/h

x: maximum spring compression = 1.5 cm = 0.015m

You need to resolve equation (1) for k. Beforehand, convert the speed v to meters per second:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant calculates to 23045 N/m

3 0
3 months ago
How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?
alisha [2963]
The result is 4.16 L. Based on the provided information, we calculated the following: Molarity = 0.225 M, Quantity of KI = 0.935 moles, To find Volume: Molarity = moles/Volume, hence Volume = moles/Molarity. Thus, Volume = 0.935/0.225, giving Volume = 4.16 L. Consequently, 4.16 L of KI is required.
6 0
3 months ago
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