All categories

1 month ago

Enter the numbers 1 to 5 to put in order the steps for lighting a Bunsen burner.

2 answers:

9 0

To light a Bunsen burner, you should follow these essential steps: First, tidy up the surrounding area and remove any combustible items. Second, shut off the air supply. Third, activate the gas flow to the burner. Fourth, ignite the flame using a lighter. Finally, modify the air intake to regulate the size of the flame.

Tems11 [2.7K]1 month ago

7 0

Answer:

The precise sequence for lighting a Bunsen burner is as follows:

1. Remove all flammable objects such as liquids and hair from the vicinity.

2. Ignite the flame using a strike lighter.

3. Activate the gas flow to the Bunsen burner.

4. Adjust the air flow to achieve the desired flame size.

5. Finally, seal the air supply on the Bunsen burner.

Explanation:

It’s crucial to emphasize that safety procedures must be observed when operating a Bunsen burner to protect the user and the laboratory. Therefore, the steps must be performed in the prescribed order:

1. First, ensure that all flammable materials around the burner are cleared to prevent a fire from igniting once the burner is lit. It's vital to complete this step beforehand rather than after lighting.

2. and 3. The lighter should be lit before turning on the gas. Activating the gas beforehand could lead to dangerous gas accumulation around the burner, potentially causing an explosion when the lighter is ignited. Thus, the lighter is first ignited, followed by a careful and gradual activation of the gas supply to light the burner.

4. Afterwards, adjust airflow gradually to achieve an optimal flame size. When a blue flame appears, adjustments should cease.

5. Once finished using the burner, the air supply must be securely closed off to prevent gas leaks.

Additionally, ensure that the gas cylinder is not located in the same room as the burner and that a fire extinguisher is on hand in case of emergencies.

You might be interested in

"A sample of silicon has an average atomic mass of 28.084amu. In the sample, there are three isotopic forms of silicon. About 92

lorasvet [2795]

Answer: The percentage abundance for $_{14}^{30}\textrm{Si}$ isotope is 3.09 %.

Explanation:

The average atomic mass of an element is calculated by taking the sum of the masses of all isotopes weighted by their respective natural fractional abundances.

To compute average atomic mass, the following formula is applied:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

From the information provided:

Let the fractional abundance for $_{14}^{28}\textrm{Si}$ isotope be 'x'

For $_{14}^{28}\textrm{Si}$ isotope:

Mass of $_{14}^{28}\textrm{Si}$ isotope = 27.9769 amu

Percentage abundance of $_{14}^{28}\textrm{Si}$ isotope = 92.22 %

Fractional abundance for $_{14}^{28}\textrm{Si}$ isotope = 0.9222

For $_{14}^{29}\textrm{Si}$ isotope:

Mass of $_{14}^{28}\textrm{Si}$ isotope = 28.9764 amu

Percentage abundance for $_{14}^{28}\textrm{Si}$ isotope = 4.68%

Fractional abundance of $_{14}^{28}\textrm{Si}$ isotope = 0.0468

For $_{14}^{30}\textrm{Si}$ isotope:

Mass of $_{14}^{30}\textrm{Si}$ isotope = 29.9737 amu

Fractional abundance for $_{14}^{30}\textrm{Si}$ isotope = x

The average atomic mass of silicon is 28.084 amu

By inserting these values into equation 1, we derive:

$28.084=[(27.9769\times 0.9222)+(28.9764\times 0.0468)+(29.9737\times x)]\\\\x=0.0309$

To convert this fractional abundance into a percentage, multiply by 100:

$\Rightarrow 0.0309\times 100=3.09\%$

This shows that the percentage abundance for $_{14}^{30}\textrm{Si}$ isotope is 3.09 %.

6 0

1 month ago

The concentration of Si in an Fe-Si alloy is 0.25 wt%. What is the concentration in kilograms of Si per cubic meter of alloy?

KiRa [2933]

Answer: The mass of Si in kilograms is, $19.55kg/m^3$

Explanation:

Given that the Si concentration in an Fe-Si alloy is 0.25 weight percent, this translates to:

Mass of Si = 0.25 g = 0.00025 kg

Mass of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg

Density of Si = $2.32g/cm^3=2.32\times 10^6g/m^3$

Density of Fe = $7.87g/cm^3=7.87\times 10^6g/m^3$

Next, we need to find the quantity of Si in kilograms per cubic meter of alloy.

Si concentration in kilograms = $\frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}$

Si concentration in kilograms = $\frac{\text{Weight of Si in 100 g of alloy}}{\frac{\text{Wight of Fe}}{\text{Density of Fe}}+\frac{\text{Wight of Si}}{\text{Density of Si}}}$

By substituting all the provided values into this formula, we arrive at:

Si concentration in kilograms = $\frac{0.00025kg}{\frac{99.75g}{7.87\times 10^6g/m^3}+\frac{0.25g}{2.23\times 10^6g/m^3}}$

Si concentration in kilograms = $19.55kg/m^3$

Hence, the mass of Si in kilograms is, $19.55kg/m^3$

5 0

1 month ago

One cubic millimeter (mm3) of blood contains 7.0 x 106 red blood cells. How many red blood cells are in 1.0 L of blood?

Anarel [2989]

The problem provides a conversion factor---> 1 mm3= 7.0 x 10^6 RBC. Therefore, to determine the quantity of red blood cells in your sample, we must first convert Liters to cm3 using the conversion factor--> 1 mL= 1 cm3

I have shared how to resolve this issue.

7 0

17 days ago

A chemist is looking for an element that reacts similarly to the element lithium (LI). Which would be the best choice?

lions [2927]

Option d is the correct choice, as both belong to the alkali metals category (group one).

8 0

1 month ago

Read 2 more answers

What are the respective central-metal oxidation state, coordination number, and overall charge on the complex ion in Na2[Cr(NH3)

lions [2927]

Answer:

Central metal oxidation state: +2

Coordination number: 6

Overall charge: -2

Explanation:

For the ion complex:

Na₂[Cr(NH₃)₂(NCS)₄]

The central metal is chromium, with NH₃ and NCS as the ligands.

NH₃ acts as a neutral ligand, while NCS carries a negative charge.

The entire complex has a charge of:

2Na⁺ + [Cr(NH₃)₂(NCS)₄]⁻² → -2

Since each NCS contributes -1 and there are four NCS, the Cr must possess an oxidation state of +2 to achieve an overall charge of -2.

With 2 NH₃ and 4 NCS attached, the coordination number sums to 2+4 = 6

I trust this clarifies the matter!

6 0

1 month ago