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pshichka
1 month ago
15

What volume is occupied by 0.34 moles of Helium gas?

Chemistry
2 answers:
alisha [2.9K]1 month ago
6 0

Answer:

I'm guessing you're referring to

STP (Standard Temperature and Pressure)

21

3

≈

7 L

Explanation:

Given that

1 mole

of an ideal gas occupies

22.4 L

when at

STP

, we can set up these relationships:

22.4 L

1 mole

or

1 mole

22.4 L

<pUsing this, we can calculate the volume for the helium gas,

0.35

mole

1

⋅

22.4 L

1

mole

=

7.84 L

which is

7.84 L

−

−

−

−

−

This result is logical because with

1 mole

occupying

22.4 L

, a fraction of that for

0.35 moles

(approximately one-third) would be close to a third of

22.4 L

(

if estimating

22.4 L as 21 L

)

−

−

−

21

3

≈

7 L

lions [2.9K]1 month ago
5 0

Response:

0.65882352941

Justification:

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Answer:

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lions [2927]

The visual representation is displayed in the following image.

For calculations, consider 100 grams of the compound:

ω(Cl) = 85.5% ÷ 100%.

ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.

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n(Cl) = m(Cl) ÷ M(Cl).

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4 0
1 month ago
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In KCI how are the valence electrons distributed
eduard [2782]

Answer:

Explanation:

In KCl, the two elements that combine to create KCl are potassium (K) and chlorine (Cl).

Potassium, as a Group 1 element, possesses one valence electron in its outermost shell which it readily donates during bonding. Every element aims to achieve a stable electron configuration, typically with 2 or 8 electrons in its outer shell. Potassium is characterized by its lower electronegativity and higher ionization energy, making it more likely to donate its electron than to accept one. On the other hand, chlorine belongs to Group 17 and has 7 electrons in its outer shell, requiring just one additional electron to complete its octet. Chlorine’s higher electronegativity and lower ionization energy facilitate its tendency to accept an electron rather than donate it.

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Answer:

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Explanation:

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