Consider the equilibrium describing the endothermic dissolution of a solid in water. Z n ( O H ) 2 ( s ) − ⇀ ↽ − Z n 2 + ( a q )

The new volume will be 33.5 L.

Explanation:

The kinetic theory of gases indicates that the space occupied by gas molecules is directly proportional to their temperature while being inversely proportional to the pressure. Assuming the number of moles is n = 1, the equation for gases can be written as:

PV = nRT

In this equation, P stands for pressure, V represents volume, R is the gas constant, and T denotes temperature.

Given that P = 523 Torr, T = 7.50 °C = 7.50 + 273.15 = 280.65 K, and the gas constant R = 62.363 Torr L mol⁻¹K⁻¹.

Consequently, the new volume will be 33.5 L.

Response:The ethanol percentage is 0.1093%

Explanation:

As given:

t = time = 10 s

I = current = 320 mA

F = Faraday's constant = 96485.3365 C mol⁻¹

n = number of electrons transferred = 4

Molecular weight of ethanol is 46 g/mol

Question: What is the percent (by volume) of ethanol in the driver's breath, %E =?

First, calculate the ethanol mass:

The moles of ethanol:

Applying the ideal gas law formula:

Here:

T = 26°C = 299 K

P = 1 atm

Substituting in the values:

The percentage of ethanol:

%

<span>To calculate the area of a sheet of paper in square centimeters, one must first transform the paper dimensions into centimeters. This can be done by multiplying 8.5 by 2.54 and 6.5 by 2.54. The resultant paper dimensions are 21.59cm by 16.51cm. The area is then determined by multiplying these dimensions, yielding an area of 356.4509cm2</span>

The temperature difference after 3 hours is 5.16 K. Given that the moles of O₂ inhaled rate at 0.02 mole/min, which converts to 1.2 mole/hour, we know the average heat released during metabolism is 7.2 kJ/h·kg. Therefore, the amount of heat generated within 3 hours will be 7.2 kJ/h·kg multiplied by 3 hours, giving a result of 21.6 kJ/kg, or 21.6 x 10³ J/kg. Applying the formula Qp = Cp x ΔT, and taking the body's heat capacity to be 4.18 J/g·K, we find ΔT = 5.16 K.

Answer:

The mass of copper generated is 19.07g

Explanation:

Let's write out the chemical equation;

3CuCl2 + 2Al → 2AlCl3 + 3Cu

3:   2:   2: 3

After confirming that the reaction is balanced, we can continue.

The problem asks for the mass of Cu produced from 5.4g of Al reacting.

Based on the equation, what is the relation between Al and Cu?

2 moles of Al would yield 3 moles of Cu

Expressing this in mass terms, we find;

mass = number of moles * molar mass

Mass of Aluminium = 2 * 26.98 = 53.98 g

Mass of Copper = 3 * 63.546 = 190.638g

This indicates that;

53.98 g of Al would react to create 190.638g of Cu

So, how much Cu would result from 5.4 g of Al?

This leads us to;

53.98 = 190.638

5.4 = x

By cross multiplication, we determine;

x = (190.638 * 5.4) / 53.98

x = 19.07 g

The mass of copper created is 19.07g