A ball is thrown into the air and follows the parabolic path indicated by the dashed line. Use the arrows provided to indicate t

Answer:

F=126339.5N

Explanation:

To compute the force required to escape, a free-body diagram for the hatch must be drawn. We will equate the downward and upward forces, thus applying the following equation:

Fw=W+Fi+F

where

Fw=   force or weight exerted by the water column above the submarine.

To calculate Fw, we can use:

Fw=h. γ. A

h=height

γ= specific weight of seawater = 10074N / m ^ 3

A=Area

Fw=28x10074x0.7=197467N

w represents the hatch weight = 200N

Fi denotes the internal pressure force in the submarine, which is 1 atm = 101325Pa. We can calculate this force using:

Fi=PA=101325x0.7=70927.5N

Finally, the force needed to open the hatch is determined by the original equation:

Fw=W+Fi+F

F=Fw-W+Fi

F=197467N-200N-70927.5N

F=126339.5N

Calculating the average speed is straightforward by using the formula involving distance and time:

average speed = distance / time

 

Thus, we have:

average speed = 4875 ft / 6.85 minutes

<span>average speed = 711.68 ft / min</span>

Answer:

The distance before stopping is 1.52 m,

velocity is 4.0 m/s on the y-axis

Explanation:

The particle’s motion is two-dimensional due to acceleration along both the x and y axes; each axis can be addressed independently for calculations.

a) At the moment the particle starts to reverse, its velocity should be zero (Vfx = 0)

     Vfₓ = V₀ₓ + aₓ t  

     t = -  V₀ₓ/aₓ

     t = - 2.4/(-1.9)

     t=  1.26 s

When the particle stops, we calculate its position

     X1 = V₀ₓ t + ½ aₓ t²

     X1= 2.4 1.26 + ½ (-1.9) 1.26²

     X1= 1.52 m

At this point, the particle begins returning.

b) The velocity comprises both x and y components.

   For the x section, Vₓ = 0 m/s indicates a halt, but the y component retains a velocity

    Vfy= Voy + ay t

    Vfy= 0 + 3.2 1.26

    Vfy = 4.0 m/s

Thus, the velocity reads as

    V = (0 x^ + 4.0 y^) m/s

c) To graph the motion, we create a table listing position x and y at given time intervals; let's begin the calculations for equations

      X = V₀ₓ t+ ½  aₓ t²

      Y = Voy t + ½  ay t²

      X= 2.4 t + ½ (-1.9) t²

      Y= 0 + ½ 3.2 t²

      X= 2.4 t – 0.95 t²

      Y=   1.6 t²

With these equations, we construct two graphs for position against time, one for the x-axis and another for the y-axis

                       Chart for graphing

              Time (s)     x(m)            y(m)

                 0                0               0

                 0.5             0.960       0.4

          1       1.45          1.6

                 1.50      1.46      3.6

                2.00      1.00      6.4

Response:

It is important to note that for units like time and angles, the transformations aren't based on ten, as shown below:

        60 s = 1 min

        60 min = 1 h

        24 h = 1 day

Hence, for this conversion, special attention is needed

the length conversion is based on ten

Clarification:

In numerous problems, the units utilized undergo transformations via equations into alternate units referred to as derived units, and the transformation of these derived units generally results from the multiplication of the transformations of the basic units.

For instance, in the context of velocity, its derived unit is expressed as m / s; therefore, the transformation operates similarly to that of length and time, meaning if they are multiplied in the equation, it continues to be multiplied, and if divided, it remains divided.

It is important to note that for units like time and angles, the transformations aren't based on ten, as shown below:

        60 s = 1 min

        60 min = 1 h

        24 h = 1 day

Hence, for this conversion, special attention is needed

the length conversion is based on ten

      1000 m = 1 km

The solutions and methods related to the exercise are included in the attached files. A detailed explanation of each step is provided below. In the archive below, you will find the required procedures, formulas, or explanations. Feel free to ask if you have any questions, and I will gladly resolve your uncertainties.