Respuesta:
Se pueden recargar.
Poseen una vida útil mayor.
Son reutilizables.
Explicación:
Las baterías de plomo-ácido y las pilas Leclanché son tipos de células electroquímicas.
Las pilas Leclanché son células primarias. Estas células producen reacciones químicas que generan corriente eléctrica de manera irreversible.
Por su parte, las baterías de plomo-ácido son células secundarias que permiten la reversibilidad de la corriente eléctrica generada.
Esto hace que las baterías de plomo-ácido sean reutilizables, con mayor durabilidad y un tiempo de vida más prolongado.
1. τbiceps = +(Positive)
2. τforearm = -(Negative)
3. τball = -(Negative)
Explanation:
The attached figure illustrates the following: 1. For the biceps, τbiceps indicates that torque is calculated as Torque = r x F, where r and F are vectors. Here, r corresponds to the vector from the elbow to the biceps. In the figure, the force from the biceps is directed upwards. Applying the right-hand rule from r to F results in counterclockwise torque, which is considered positive (+).
2. The torque related to the weight of the forearm, τforearm, uses the same torque formula, with r being the vector from the elbow to the forearm. The weight acts downward, causing a clockwise torque that is negative (-).
3. Similarly, for the weight of the ball, τball, the downward force from the ball's weight generates a clockwise torque, which also registers as negative (-).
Response:
Reasoning:
We will utilize a Gaussian surface that resembles the curved wall of a cylinder, with a radius of 3mm and a length of 1 unit directed parallel to the wire axis.
The charge within this cylinder amounts to 250 x 10⁻⁹ C.
Let E denote the electric field at the curved surface, perpendicular to it.
The total electric flux leaving the curved surface
is calculated as 2π r x 1 x E
or 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's law, the total flux is given by the charge within divided by ε (the charge inside the cylinder being 250 x 10⁻⁹C)
equals 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² (where ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹²)
resulting in 11.3 x 10³ weber.
Thus,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
=.599 x 10⁶ N /C.
Answer:
R=V/I=6/2=3 ohm
time = 5 minutes = 5*60=300 seconds
I=2 A
Energy = I²Rt=(2)²*3*300=4*900=3600 J
Answer:
The driveway measures 4.98 m
Explanation:
We aim to find the length of the driveway, thus utilizing the following equations
W=ΔK.E where W represents work and ΔK.E indicates the change in kinetic energy
Moreover,
also
W = F.d where F is the force and d denotes distance
Given that
= 4000 N indicating this frictional force
m = 2100 Kg
θ= 20.0°
V=3.8 m/s representing the car's speed at the bottom of the driveway
W=Δ K.E
= 15162 J
As the x component of gravity is
= mg sinФ
thus
= (2100)(9.8)sin(20.0°) results in
= 7038.77 N
And the Net force is
=
-
= 7038.77 - 4000 = 3038.77 N
So, the length of the driveway equals W / (
) = 15162/3038.77 = 4.98 m
Thus, this is the length of the driveway.
