A 0.1153-gram sample of a pure hydrocarbon was burned in a C-H combustion train to produce 0.3986 gram of CO2and 0.0578 gram of
1 answer:
Answer: The carbon and hydrogen masses in the sample are 0.1087 g and 0.0066 g, respectively, with percentage compositions of 94.27 % for carbon and 5.72 % for hydrogen.
Explanation:
The combustion equation for the hydrocarbon containing carbon and hydrogen is expressed as follows:
where 'x' and 'y' denote the subscripts for carbon and hydrogen.
Given:
Mass of
Mass of
Total mass of the sample = 0.1153 g
We understand that:
Molecular weight of carbon dioxide = 44 g/mol
Molecular weight of water = 18 g/mol
- To find the mass of carbon:
In 44 g of carbon dioxide, there are 12 g of carbon.
This implies that in 0.3986 g of carbon dioxide, will represent the carbon contained.
- To find the mass of hydrogen:
In 18 g of water, there are 2 g of hydrogen.
<pso in="" g="" of="" water="" src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B18%7D%5Ctimes%200.0578%3D0.0066g" id="TexFormula5" title="\frac{2}{18}\times 0.0578=0.0066g" alt="\frac{2}{18}\times 0.0578=0.0066g" align="absmiddle" class="latex-formula"> will represent the hydrogen contained.To compute the percentage composition of a substance in a sample, we apply the following equation:
......(1)
- For Carbon:
Mass of sample = 0.1153 g
Mass of carbon = 0.1087 g
Substituting into equation 1 yields:
- For Hydrogen:
Mass of sample = 0.1153 g
Mass of hydrogen = 0.0066 g
Substituting into equation 1 yields:
Consequently, the carbon and hydrogen masses in the sample are 0.1087 g and 0.0066 g, respectively, with percentage compositions of 94.27 % for carbon and 5.72 % for hydrogen.
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Response:
The specific heat of the alloy
Clarification:
Weight of the alloy = 25 gm
Initial temperature = 100°c = 373 K
Weight of the water = 90 gm
Initial temperature of water = 25.32 °c = 298.32 K
Final temperature = 27.18 °c = 300.18 K
Using the energy balance equation,
Heat released by the alloy = Heat absorbed by the water
[[
-
] =
(
-
)
25 × × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)
This gives us the specific heat of the alloy.