The cantilever beam AB has a rectangular cross section of 150 × 200 mm. Knowing that the tension in the cable BD is 10.8 kN and

Answer:

The flux across the cube's surface is .

Solution:

According to the details provided:

Cube edge length, a = 8.0 cm = .

Volume charge density, .

Now,

To find the electric flux:

where

= electric flux

= permittivity of vacuum.

The volume charge density for this scenario is described by:

Cube volume, .

Thus,

.

The total charge can be derived from equation (2):

.

.

Now, insert the value of 'q' into equation (1):

.

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

Conversely, in darkness, the diameter typically enlarges to 7 mm.

This indicates an increase in light-gathering capacity.

Thus, the amount of light the eye can capture is 31.4 mm².

Answer:

12.1 seconds

Explanation:

t = time duration

u = initial speed

v = final speed = 0

s = distance = 120 m

a = lunar gravity acceleration = 1.67 m/s²

Motion equation

The rock takes 12.1 seconds to reach the bottom of the crater.

The answer is letter d, 8.3.

Here’s a solution for the given problem:

We have:

B = 6i - 8j 

Let A be unknown; we'll denote A as = mi + nj 

The resultant A+B lies along the x-axis (which implies A+B = Ki + 0j, where K is yet to be determined,

and we also know the magnitude of A+B is equivalent to the magnitude of A,

therefore, mag(A+B)=K=sqrt(m^2+n^2), or K^2 = m^2+n^2. 

Using vector addition, A+B becomes (m+6)i + (n-8)j.

Since we know A+B = Ki + 0j, we can establish that: 

m + 6 = K 

n - 8 = 0, which gives n=8. 

Thus, K^2=m^2+n^2 means (m+6)^2 = m^2 +8^2 

= m^2 + 12m + 36 = m^2 + 64 

which gives us 12m = 28 

m = 2.33333... 

Consequently, the magnitude of A is sqrt[(2.333...)^2 + 8^2] = 8.3333.