A spring with a spring constant of 2500 n/m. is stretched 4.00 cm. what is the work required to stretch the spring?
2 answers:
The energy needed to stretch the spring amounts to approximately 2.0 Joules
Further explanation
Let’s revisit the formula for Elastic Potential Energy:
where:
Ep = elastic potential energy ( J )
k = spring constant ( N/m )
x = spring extension ( or compression ) ( m )
Now, let’s solve the problem!
Given:
spring constant = k = 2500 N/m
extension = x = 4.00 cm = 4.00 × 10⁻² m
Asked:
work needed = W =?
Solution:
We will determine the work necessary to stretch the spring as follows:
Conclusion:
The energy required to stretch the spring is approximately 2.0 Joules
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Answer details
Grade: High School
Subject: Physics
Chapter: Elasticity
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